Answer:
non linear square relationship
Explanation:
formula for centripetal force is given as
a = mv^2/r
here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have
a = constant × v^2
a α v^2
hence non linear square relationship
To do this you would take 64 and divide it by 4.
64/4= 16.
Your answer is 16.
Hi there!
Since the object is being pulled at a constant velocity, the forces must be balanced.
Since there is no movement vertically, we must take into account the horizontal forces. We can also assume a positive acceleration to be in the direction of motion.
The acceleration and force due to gravity on an incline is:
a = gsinФ
F = MgsinФ
∑F = -MgsinФ + T
Since it is getting pulled at a constant velocity, ∑F = 0. So:
0 = -MgsinФ + T
MgsinФ = T
Solve for T by plugging in values. Let g = 10 m/s²
T = (120)(10)sin(27) ≈ 545 N
<span>Three-fourths of the illuminated side of the moon be visible
from Earth when the moon is at position-B. (choice-B)
Notice the particularly egregious screw-up on the drawing at the
"Third Quarter" position. There, the drawing shows the illuminated
side of the moon AWAY from the sun, and the dark side of the moon
TOWARD the sun. That's about as silly as you can get. </span>
Present day earth is in the Cenozoic era and the time period for it is 66 million years ago to today.
