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2 years ago

Solids diffuse because the particles cannot move.

Physics

2 answers:

VLD [36.1K]2 years ago

6 0

Answer: C. Cannot
They don’t space to move.

Nastasia [14]2 years ago

4 0

Solids cannot diffuse.

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A cat is moving at 18 m/s when it accelerates for 2 seconds. What is its acceleration?

vova2212 [387]

Answer: acceleration: $4 m/s^{2}$

velocity: $26 m/s$

Explanation:

The complete question is written bellow:

A cat is moving at 18 m/s when it accelerates at $4 m/s^{2}$ for 2 seconds. What is his new velocity?

In this situation the following equation will be useful:

$V=V_{o}+at$

Where:

$V$ is the cat’s final velocity (new velocity)

$V_{o}=18 m/s$ is the cat’s initial velocity

$a=4 m/s^{2}$ is the cat's acceleration

$t=2 s$ is the time

Solving the equation:

$V=18 m/s+(4 m/s^{2})(2 s)$

$V=26 m/s$ This is the cat's new velocity

5 0

2 years ago

A cyclist rides 6.3 km east for 21 minutes, then he turns and heads west for 6 minutes and 1.8 km. Finally, he rides east for 13

Leona [35]

Answer:

$\vec{d}=17.7km$

Explanation:

Displacement is a vector that defines the position of a particle. The vector extends from the initial position to the final position. Therefore, the displacement only takes into account this positions, since its trajectory is not important:

$\vec{d}=6.3km-1.8km+13.2km\\\vec{d}=17.7km$

6 0

3 years ago

Need Help.

zaharov [31]

Newton’s fifth law says so i’m sorry it’s just logic

7 0

2 years ago

A 5.00 g bullet traveling 355 m/s is stopped by lodging in the side of a building. The heat produced is shared between the build

steposvetlana [31]

Answer:

Explanation:

Given

mass of bullet $m=5\ gm$

speed of bullet $v=355\ m/s$

bullet is stopped by building and heat produced is shared between building and bullet

Kinetic Energy of bullet is converted into Thermal energy

Kinetic Energy of bullet $K=\frac{1}{2}mv^2$

$K=0.5\times 5\times 10^{-3}\times (355)^2$

$K=315.06\ J$

So 315.06 J of Energy is converted in to thermal energy

7 0

3 years ago

The basic barometer can be used to measure the height of a building. If the barometric readings at the top and at the bottom of

LekaFEV [45]

Answer:

(h₁-h₂) = 2.30 10² m

Explanation:

The pressure depends on the height with the formula

P = P_atm + rho g h

Let's apply this expression for the building

P₁ = P_atm + rho_air g h₁

P₂ = P_atm + rho_air g h₂

Subtract

P₁ - P₂ = roh_air g (h₁ –h₂)

The measured pressure is in mm Hg to take this unit to units of pressure must be multiplied by the density of mercury and the acceleration of gravity

P₁- P₂ = rho_Hg g (h₁-h₂) _Hg

rho_Hg g (h₁-h₂) _Hg = roh_air g (h₁ –h₂)

(h₁ –h₂) = rho_Hg / rho_air (h₁-h₂) _ Hg

Let's calculate

(h₁-h₂) = 13600 / 1.18 (695-675)

(h₁-h₂) = 2.30 10⁵ mm

Let's reduce to meter

(h₁-h₂) = 2.30 10⁵ mm (1 m / 10³ mm)

(h₁-h₂) = 2.30 10² m

4 0

2 years ago