1.47x10^5 Joules
The gravitational potential energy will be the mass of the object, multiplied by the height upon which it can drop, multiplied by the local gravitational acceleration. And since it started at the top of a 60.0 meter hill, halfway will be at 30.0 meters. So
500 kg * 30.0 m * 9.8 m/s^2 = 147000 kg*m^2/s^ = 147000 Joules.
Using scientific notation and 3 significant figures gives 1.47x10^5 Joules.
Answer:
Explanation:
Given
there is fix Quantity of gas i.e. mass of gas is constant
From ideal gas Equation
PV=nRT
(a) volume always increases is not true as Pressure can also be increased .
(b)If Pressure is constant along with mass then as Temperature increases, Volume also increases.
(c)true , Product of Pressure and volume depends upon temperature thus it also increases with temperature.
(d)Density of gas may or may not increases
As density is ![\frac{mass}{volume}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D)
volume may increase or decrease as temperature increase .
(e)false
as it clearly stated that quantity of fixed therefore there is no change in gas
Answer:
2.The forces are unbalanced.
5.The net force is to the right.
6.The book is moving to the right.
Explanation:
correct on edge :)
Answer: The taxi is moving with reference to A) Monument Circle. For each leg of the trip, the taxi's A) Average speed stays the same, but it's B) Average velocity changes.
Explanation: Brainliest Please!!!!
Answer:
28716.4740661 N
1.2131147541 m/s
51.2474965841%
Explanation:
m = Mass of plane = 74000 kg
s = Displacement = 3.7 m
f = Frictional force = 14000 N
t = Time taken = 6.1 s
u = Initial velocity = 0
v = Final velocity
![s=ut+\frac{1}{2}at^2\\\Rightarrow 3.7=0\times 6.1+\frac{1}{2}\times a\times 6.1^2\\\Rightarrow a=\frac{3.7\times 2}{6.1^2}\\\Rightarrow a=0.198871271164\ m/s^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%203.7%3D0%5Ctimes%206.1%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%206.1%5E2%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B3.7%5Ctimes%202%7D%7B6.1%5E2%7D%5C%5C%5CRightarrow%20a%3D0.198871271164%5C%20m%2Fs%5E2)
Force is given by
![F=ma+f\\\Rightarrow F=74000\times 0.198871271164+14000\\\Rightarrow F=28716.4740661\ N](https://tex.z-dn.net/?f=F%3Dma%2Bf%5C%5C%5CRightarrow%20F%3D74000%5Ctimes%200.198871271164%2B14000%5C%5C%5CRightarrow%20F%3D28716.4740661%5C%20N)
The force with which the team pulls the plane is 28716.4740661 N
![v=u+at\\\Rightarrow v=0+0.198871271164\times 6.1\\\Rightarrow v=1.2131147541\ m/s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20v%3D0%2B0.198871271164%5Ctimes%206.1%5C%5C%5CRightarrow%20v%3D1.2131147541%5C%20m%2Fs)
The speed of the plane is 1.2131147541 m/s
Kinetic energy is given by
![K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}\times 74000\times 1.2131147541^2\\\Rightarrow K=54450.9540448\ J](https://tex.z-dn.net/?f=K%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%5C%5C%5CRightarrow%20K%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%2074000%5Ctimes%201.2131147541%5E2%5C%5C%5CRightarrow%20K%3D54450.9540448%5C%20J)
Work done is given by
![W=Fs\\\Rightarrow W=28716.4740661\times 3.7\\\Rightarrow W=106250.954045\ J](https://tex.z-dn.net/?f=W%3DFs%5C%5C%5CRightarrow%20W%3D28716.4740661%5Ctimes%203.7%5C%5C%5CRightarrow%20W%3D106250.954045%5C%20J)
The fraction is given by
![\dfrac{54450.9540448}{106250.954045}=0.512474965841](https://tex.z-dn.net/?f=%5Cdfrac%7B54450.9540448%7D%7B106250.954045%7D%3D0.512474965841)
The teams 51.2474965841% of the work goes to kinetic energy of the plane.