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IgorC [24]
3 years ago
6

please help In a video game, a ball moving at 0.6 meter/second collides with a wall. After the collision, the velocity of the ba

ll changed to -0.4 meter/second. The collision takes 0.2 seconds to occur. What’s the acceleration of the ball during the collision? Use . a= v-u/t
Physics
1 answer:
viva [34]3 years ago
4 0

Answer:

the acceleration during the collision is: - 5  \frac{m}{s^2}

Explanation:

Using the formula:

a=\frac{\Delta\,v}{\Delta\,t}

we get:

a=\frac{-0.4-0.6}{0.2} \,\frac{m}{s^2} =\frac{-1}{0.2} \,\frac{m}{s^2} =-5\,\,\frac{m}{s^2}

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What is the force in N of an object that has a mass of 7 kilograms and an acceleration of 4 m/s/s
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Newton's 2nd law of motion:         Force = (mass) x (acceleration)

If you want to move a 7-kg object with an acceleration of 4 m/s²,
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3 years ago
newton's second law states that when a net force acts on an object, it accelerates it.Explain how it would be possible for two o
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See Explanation

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2 years ago
PLEASE HELP ME A lens with a surface that curves outward like the exterior of a sphere is __________. (Points : 1) reflected ref
yanalaym [24]
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3 0
3 years ago
Read 2 more answers
The central star of a planetary nebula emits ultraviolet light with wavelength 104nm. This light passes through a diffraction gr
Gala2k [10]

Answer: 31.33 degrees

Explanation:

The diffraction angles \theta_{n} when we have a slit divided into n parts are obtained by  the following equation:

dsin\theta_{n}=n\lambda   (1)

Where:

d is the width of the slit

\lambda  is the wavelength of the light

n is an integer different from zero.

Now, the first-order diffraction angle is given when n=1, hence equation (1) becomes:

dsin\theta_{1}=\lambda   (2)

Now we have to find the value of \theta_{1}:

sin\theta_{1}=\frac{\lambda}{d}  

\theta_{1}=arcsin(\frac{\lambda}{d})   (3)

We know:

\lambda=104nm=104(10)^{-9}m

In addition we are told the diffraction grating has 5000 slits per mm, this means:

d=\frac{1mm}{5000}=\frac{1(10)^{-3}m}{5000}

Substituting the known values in (3):

\theta_{1}=arcsin(\frac{104(10)^{-9}m}{\frac{1(10)^{-3}m}{5000}})

\theta_{1}=arcsin(0.52)

<u>Finally:</u>

\theta_{1}=31.33\º >>>This is the first-order diffraction angle

4 0
2 years ago
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