Explanation:
A charge alters the space around it. This alteration of space is called the electric field. It is also defined as the electric force acting on a charged particle per unit test charge. It is given by :

Where
F is the electric force, 
The direction of electric field is in the direction of electric force. For a positive charge, the direction of electric field lines are outwards and for a negative charge, the direction of field lines are inwards.
Hence, the correct option is (c) "electric field".
 
        
             
        
        
        
Definition:                   Momentum  =  (mass) x (speed)
OK. Here we go.
Watch closely:
Divide each side         
by  'mass' :                  <span>Momentum / mass  =  Speed </span>
Did you follow that ?
        
             
        
        
        
Answer:
how much space it takes up in the world
Explanation:
1) Mass is a measurement of the amount of matter something contains, while Weight is the measurement of the pull of gravity on an object. 2) Mass is measured by using a balance comparing a known amount of matter to an unknown amount of matter. Weight is measured on a scale.
 
        
             
        
        
        
-- <u><em>Current is measured in amps.</em></u>  (You can use any symbol you want to represent current, but the most common one is " I ", not "Δ".) 
-- <u><em>The relationship between current, voltage, and resistance is mathematically defined by Ohm's Law. </em></u>
-- <u><em>Current is the flow of electrons through a circuit.</em></u> 
-- (Ohm's Law is NOT mathematically represented by the equation V=I/R.)  <u><em>It should be V = I · R</em></u> .  
(When solving for Resistance in a circuit and both voltage and current are known values, the equation I =V*R is not true, and not the way to solve it.)  <u><em>If the resistance is what you're looking for, then the equation to use is  </em></u><u><em>R = V / I</em></u><u><em> .  </em></u> 
<em>-- </em><u><em>If the voltage in a circuit is increased, the current will also increase.</em></u>