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3 years ago

5

Which sentence contains a pronoun with an unclear, a missing, or a confusing antecedent?

1 answer:

Arte-miy333 [17]3 years ago

6 0

Answer:

B. They say that doing homework leads to his success in school.

Step-by-step explanation:

Looking at the answers, C and D already make sense, so they're not the answers. The answer A does not have an unclear antecedent because "my mom and me" would not be written as "my mom and I". B is the only answer left. If you look at the sentence, it begins with "they", and it ends up saying "his success in school". This sentence includes a confusing antecedent because the sentence does not define the person who it is describing.

Sorry if this explanation was confusing. I hope this helps! Have a great day!! C:

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Plz, answer! 34 + 2 ⋅ 5 =

8_murik_8 [283]

$3^{4}$ + 2 × 5

To evaluate apply the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

Parentheses

There are none for this steps so go on to the next step

Exponent:

$3^{4}$

81

so...

81 + 2 × 5

Multiplication:

81 + 2 × 5

2 × 5

10

so...

81 + 10

No division in this equation so skip this step and go to the next one

Addition:

81 + 10

91

Hope this helped!

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Josh's sit had 20,313 more visitors than Diego's.

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3 years ago

PLEASE HELP I WILL HELP YOU

Sidana [21]

Answer:

5 is the answer

Step-by-step explanation:

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2 years ago

10=12-x what would match this equation

Eddi Din [679]

Answer:

x=2

Step-by-step explanation:

12-10=2

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4 years ago

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A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12. Suppose that we take a random

Zielflug [23.3K]

Answer: The 95% confidence interval for the mean of x is (94.08, 101.92) .

Step-by-step explanation:

We are given that ,

A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12.

i.e. $\sigma= 12$

Also, it is given that , Sample mean $\overline{x}=98$ having sample size : n= 36

For 95% confidence ,

Significance level : $\alpha=1-0.95=0.05$

By using the z-value table , the two-tailed critical value for 95% Confidence interval :

$z_{\alpha/2}=z_{0.025}=1.96$

We know that the confidence interval for unknown population mean $(\mu)$ is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = Sample mean

$\sigma$ = Population standard deviation

$z_{\alpha/2}$ = Critical z-value.

Substitute all the given values, then the required confidence interval will be :

$98\pm (1.96)\dfrac{12}{\sqrt{36}}$

$=98\pm (1.96)\dfrac{12}{6}$

$=98\pm (1.96)(2)$

$=98\pm 3.92=(98-3.92,\ 98+3.92)\\\\=( 94.08,\ 101.92)$

Therefore, the 95% confidence interval for the mean of x is (94.08, 101.92) .

6 0

3 years ago