Depends on how the sword is made, what materials are used and temperature used but yes they can shatter.
When molecules cool down they stop vibrating and moving as much and so they "shrink" and the metal of the sword becomes brittle. sometimes they shrink at different phases which cause tension in the sword if this tension is strong enough it can cause the metallic bonds to break causing the sword to shatter.
hope that helps
Answer:
The ratio of pressure in bottle B to that of bottle A is 1 : 4
Explanation:
We'll be by calculating the pressure in both bottles. This is illustrated below below:
For A:
Temperature (T) = T
Volume (V) = V
Number of mole (n) = n
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =...?
PV = nRT
PV = n x 0.0821 x T
Divide both side by V
P = nT0.0821/V
Therefore, the pressure, in bottle A is
PA = nT0.0821/V
For B:
Temperature (T) = the same as that of A = T
Volume (V) = twice that of A = 2V
Number of mole (n) = half that of A = ½n
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =...?
PV = nRT
P x 2V = ½n x 0.0821 x T
Divide both side by 2V
P = ½n x 0.0821 x T/2V
P = nT0.0821/4V
Therefore, the pressure in bottle B is:
PB = nT0.0821/4V
Now, we can obtain the ratio of pressure in bottle B to that of bottle A as follow:
Pressure in bottle A (PA) = nT0.0821/V
Pressure in bottle B (PB) = nT0.0821/4V
PB/PA = nT0.0821/4V ÷ nT0.0821/V
PB/PA = nT0.0821/4V x V/nT0.0821
PB/PA = 1/4
Therefore, the ratio of pressure in bottle B to that of bottle A is 1 : 4.
Hello
V= m/p when V= volume, m, mass and p the density
then
V=18754000/0,7888
Remember that you first have to convert kg to gr, simply multiplied by 1000.
then
V= 23799492 cm3
Best regards
Answer:
2.29 m.
Explanation:
The following data were obtained from the question:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mass of water = 329 g
Molality of KOH = ?
Next, we shall determine the number of mole in 42.3 g of KOH. This can be obtained as follow:
Mass of KOH = 42.3 g
Molar mass of KOH = 56.11 g/mol
Mole of KOH =?
Mole = mass /Molar mass
Mole of KOH = 42.3/56.11
Mole of KOH = 0.754 mole
Next, we shall convert 329 g of water to kilogram (kg). This can be obtained as follow:
1000 g = 1 kg
Therefore,
329 g = 329 g /1000 g × 1 kg
329 g = 0.329 kg
Therefore, 329 g of water is equivalent to 0.329 kg
Finally, we shall determine the molality of the KOH solution ad follow:
Molality is defined as the mole of solute per unit kilogram of solvent (water) i.e
Molality = mole/ mass (kg) of water
Mole of KOH = 0.754 mole.
Mass of water = 0.329 kg.
Molality = mole/ mass (kg) of water
Molality = 0.754/0.329
Molality = 2.29 m
Therefore, the molality of the KOH solution is 2.29 m.
