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2 years ago

How can people stop being Homophobia? °∩°

Physics

2 answers:

Alex787 [66]2 years ago

7 0

Pretty long so read if you will:

I'm pretty late to this but oh well. Well to start why are people homophobic in the first place? You might not understand as well but that is because me and you are growing up at a time and place where people are encouraged to be themselves and we're embracing people that are different than what is considered normal. Gay marriage was legalized literally in the US in 2015, 5 years ago. I come from Malaysia, one of the few countries where it's illegal to be gay and can cause a death penalty from what I've seen. Obviously I grew up in a place where gay and whatnot were a joke and is wrong. But we moved and I came to the US and my beliefs changes, it also helped that I was literally only 11 so I was more easier to change than adults. Majority of the world honestly, are not as open to the lgbtq+ community as a person in America might think. The belief that it's only a women and men probably stems from the fact that it's how u make babies. And if we know anything, society doesn't like things that are different. To stop people being homophobic you have to stop people from spreading the belief that it's wrong to be gay or bi. This is going to be hard and people really overestimate the world when it comes to change. Peoples belief won't be changed so quick just, change doesn't happen quick. It's going to be a long time and maybe even never, look at racism. We all exist together for so long but there's still racism though much less compared to back then. As long as people stop teaching that next generation, us, that being lgbtq+ is bad, it will decrease but it will take a long time. And as much as I agree we need it to be now, it won't and trying to force something will only cause more backlash. Just try to inform the people around you and understand change does not happen fast, it's slow, especially if it you want it to be permanent.

OLEGan [10]2 years ago

5 0

Answer:

sure

Explanation:

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At a depth of 1030 m in Lake Baikal (a fresh water lake in Siberia), the pressure has increased by 100 atmospheres (to about 107

dangina [55]

Answer:

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

Explanation:

The bulk modulus is represented by the following differential equation:

$K = - V\cdot \frac{dP}{dV}$

Where:

$K$ - Bulk module, measured in pascals.

$V$ - Sample volume, measured in cubic meters.

$P$ - Local pressure, measured in pascals.

Now, let suppose that bulk remains constant, so that differential equation can be reduced into a first-order linear non-homogeneous differential equation with separable variables:

$-\frac{K \,dV}{V} = dP$

This resultant expression is solved by definite integration and algebraic handling:

$-K\int\limits^{V_{f}}_{V_{o}} {\frac{dV}{V} } = \int\limits^{P_{f}}_{P_{o}}\, dP$

$-K\cdot \ln \left |\frac{V_{f}}{V_{o}} \right| = P_{f} - P_{o}$

$\ln \left| \frac{V_{f}}{V_{o}} \right| = \frac{P_{o}-P_{f}}{K}$

$\frac{V_{f}}{V_{o}} = e^{\frac{P_{o}-P_{f}}{K} }$

The final volume is predicted by:

$V_{f} = V_{o}\cdot e^{\frac{P_{o}-P_{f}}{K} }$

If $V_{o} = 1\,m^{3}$ , $P_{o} - P_{f} = -10132500\,Pa$ and $K = 2.3\times 10^{9}\,Pa$ , then:

$V_{f} = (1\,m^{3}) \cdot e^{\frac{-10.1325\times 10^{6}\,Pa}{2.3 \times 10^{9}\,Pa} }$

$V_{f} \approx 0.996\,m^{3}$

Change in volume due to increasure on pressure is:

$\Delta V = V_{o} - V_{f}$

$\Delta V = 1\,m^{3} - 0.996\,m^{3}$

$\Delta V = 0.004\,m^{3}$

A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.

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Answer:

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A thin 1.5 mm coating of glycerine has been placed between two microscope slides of width 0.8 cm and length 3.9 cm . Find the fo

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The force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.

<h3>Force required to pull one end at a constant speed</h3>

The force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is determined by applying Newton's second law of motion as shown below;

F = ma

where;

m is mass
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F = m x 0

F = 0

Thus, the force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.

Learn more about constant speed here: brainly.com/question/2681210

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