Answer:
105 m/s
Explanation:
Given that the speed of train A,
= 45 m/s from west to east.
Speed of train B,
= 60 m/s from east to west.
Train B is moving in the opposite direction with respect to the speed of train A. Assuming that the speed from east to west direction is positive.
So, the speed of train A from east to west= - 45 m/s
The speed of train B w.r.t train A
m/s
Hence, the speed of train B w.r.t train A is 105 m/s from east to west.
Answer:
Because of the formula 
Explanation:
In this problem we are describing two different processes:
- Nuclear fission occurs when a heavy, unstable nucleus breaks apart into two or more lighter nuclei
- Nuclear fusion occurs when two (or more) light nuclei fuse together producing a heavier nucleus
In both cases, the total mass of the final products is smaller than the total mass of the initial nuclei.
According to Einsten's formula, this mass difference has been converted into energy, as follows:

where:
E is the energy released in the reaction
is the mass defect, the difference between the final total mass and the initial total mass
is the speed of light
From the formula, we see that the factor
is a very large number, therefore even if the mass defect
is very small, nuclear fusion and nuclear fission release huge amounts of energy.
I think that the answer to that is true hope that helps
Answer:
the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
Explanation:
Given that;
weight of vehicle = 4000 lbs
we know that 1 kg = 2.20462
so
m = 4000 / 2.20462 = 1814.37 kg
Initial velocity
= 60 mph = 26.8224 m/s
Final velocity
= 30 mph = 13.4112 m/s
now we determine change in kinetic energy
Δk =
m(
² -
² )
we substitute
Δk =
×1814.37( (26.8224)² - (13.4112)² )
Δk =
× 1814.37 × 539.5808
Δk = 489500 Joules
we know that; 1 kilowatt hour = 3.6 × 10⁶ Joule
so
Δk = 489500 / 3.6 × 10⁶
Δk = 0.13597 ≈ 0.136 kWh
Therefore, the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh