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sattari [20]
3 years ago
13

What simple machine is a ramp hammer and a knife

Chemistry
1 answer:
Elena L [17]3 years ago
8 0

Answer:

lever Levers

Types of lever

Levers are all around us. Hammers, axes, tongs, knives, screwdrivers, wrenches, scissors—all these things contain levers.

Explanation:

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PLZ HELP! I will give brainliest for best answer!!!!
AnnZ [28]

Nitrogen is 1.25 g/L

Sulfur Dioxide is 2.86 g/L

Methane is 0.174 g/L

Hope I helped :)

4 0
3 years ago
Find the mass in grams of 0.75 moles of magnesium (Mg).
Lady bird [3.3K]

Answer:

18.22874999999973

I recommend you to round the nearest 1 d.p

Explanation:

<em>h</em><em>a</em><em>v</em><em>e</em><em> </em><em>a</em><em> </em><em>g</em><em>r</em><em>e</em><em>a</em><em>t</em><em> </em><em>d</em><em>a</em><em>y</em><em>!</em>

3 0
3 years ago
Read 2 more answers
We say that salts will dissociate but acids will react with water. We say that acids will
Paha777 [63]

Answer:

ionize

Explanation:

Acids are chemical substances that lose/donate their hydrogen ion (H+) when they react with water. This property of acids is termed IONIZATION. In a chemical reaction involving acids and bases, acids release their proton or hydrogen ion (H+) in the presence of water solutions to form a conjugate base, which is usually an anion.

For example, in the chemical reaction;

HX + H20 -------> X- + H30+

HX is the acid because it loses its electron to water and forms the anion, X-, which is the conjugate base. Hence, it can be said that acid HX ionizes in water.

7 0
3 years ago
Where in the periodic table would you find elements with the same number of energy levels?
kifflom [539]

Answer:

b

Explanation:

6 0
4 years ago
Read 2 more answers
Consider the equilibrium
vladimir1956 [14]

Answer:

Kp^{1000K}=0.141\\Kp^{298.15K}=2.01x10^{-18}

\Delta _rG=1.01x10^5J/mol

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

C_2H_6(g)\rightleftharpoons H_2(g)+C_2H_4(g)

Thus, Kp for this reaction is computed based on the given molar fractions and the total pressure at equilibrium, as shown below:

p_{C_2H_6}^{EQ}=2bar*0.592=1.184bar\\p_{C_2H_4}^{EQ}=2bar*0.204=0.408bar\\p_{H_2}^{EQ}=2bar*0.204=0.408bar

Kp=\frac{p_{C_2H_4}^{EQ}p_{H_2}^{EQ}}{p_{C_2H_6}^{EQ}}=\frac{(0.408)(0.408)}{1.184}=0.141

Now, by using the Van't Hoff equation one computes the equilibrium constant at 298.15K assuming the enthalpy of reaction remains constant:

Ln(Kp^{298.15K})=Ln(Kp^{1000K})-\frac{\Delta _rH}{R}*(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=Ln(0.141)-\frac{137000J/mol}{8.314J/mol*K} *(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=-40.749\\\\Kp^{298.15K}=exp(-40.749)=2.01x10^{-18}

Finally, the Gibbs free energy for the reaction at 298.15K is:

\Delta _rG=-RTln(Kp^{298.15K})=8.314J/mol*K*298.15K*ln(2.01x10^{-18})\\\Delta _rG=1.01x10^5J/mol

Best regards.

3 0
4 years ago
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