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AysviL [449]
3 years ago
13

What is the horizontal acceleration of a ball that is launched horizontally with a velocity of 5.6 m/s?

Physics
1 answer:
sergij07 [2.7K]3 years ago
5 0
The answers to this question is the 4th one
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The topsoil layer has the greatest concentration of organic matter. The subsoil generally lacks organic matter, but it does rece
zmey [24]

Answer:

C. the C horizon likely has a rockier texture than the topsoil and subsoil.

Explanation:

because i did it on study island

3 0
3 years ago
Suppose a baseball pitcher throws the ball to his catcher.
amm1812

a) Same

b) Same

c) Same

d) Throw the ball takes longer

e) F is larger when the ball is catched

Explanation:

a)

The change in speed of an object is given by:

\Delta v = |v-u|

where

u is the initial velocity of the object

v is the final velocity of the object

The change in speed is basically the magnitude of the change in velocity (because velocity is a vector, while speed is a scalar, so it has no direction).

In this problem:

- In situation 1 (pitcher throwing the ball), the initial velocity is

u = 0 (because the ball starts from rest)

while the final velocity is v, so the change in speed is

\Delta v=|v-0|=|v|

- In situation 2 (catcher receiving the ball), the initial velocity is now

u = v

while the final velocity is now zero (ball coming to rest), so the change in speed is

\Delta v =|0-v|=|-v|

Which means that the two situations have same change in speed.

b)

The change in momentum of an object is given by

\Delta p = m \Delta v

where

m is the mass of the object

\Delta v is the change in velocity

If we want to compare only the magnitude of the change in momentum of the object, then it is given by

|\Delta p|=m|\Delta v|

- In situation 1 (pitcher throwing the ball), the change in momentum is

\Delta p = m|\Delta v|=m|v|=mv

- In situation 2 (catcher receiving the ball), the change in momentum is

\Delta p = m\Delta v = m|-v|=mv

So, the magnitude of the change in momentum is the same (but the direction is opposite)

c)

The impulse exerted on an object is equal to the change in momentum of the object:

I=\Delta p

where

I is the impulse

\Delta p is the change in momentum

As we saw in part b), the change in momentum of the ball in the two situations is the same, therefore the impulse exerted on the ball will also be the same, in magnitude.

However, the direction will be opposite, as the change in momentum has opposite direction in the two situations.

d)

To compare the time of impact in the two situations, we have to look closer into them.

- When the ball is thrown, the hand "moves together" with the ball, from back to ahead in order to give it the necessary push. We can verify therefore that the time is longer in this case.

- When the ball is cacthed, the hand remains more or less "at rest", it  doesn't move much, so the collision lasts much less than the previous situation.

Therefore, we can say that the time of impact is longer when the ball is thrown, compared to when it is catched.

e)

The impulse exerted on an object can also be rewritten as the product between the force applied on the object and the time of impact:

I=F\Delta t

where

I is the impulse

F is the force applied

\Delta t is the time of impact

This can be rewritten as

F=\frac{I}{\Delta t}

In this problem, in the two situations,

- I (the impulse) is the same in both situations

- \Delta t when the ball is thrown is larger than when it is catched

Therefore, since F is inversely proportional to \Delta t, this means that the force is larger when the ball is catched.

6 0
3 years ago
NEED THIS ASAP
horrorfan [7]

Answer:

Energy is essentially work done by an object or on object.

From,

W = Fd

It's directly proportional to mass.

from,

K. E = 1/2mv²

Energy is directly proportional to mass.

P. E = mgh

Energy is directly proportional to mass.

H = mc∆T

Energy is directly proportional to mass.

Thus increasing mass will increase the energy also imparted on another object since all the above eqns show that relationship.

And for 2 moving bodies

K.Ei = K.Ef(energy conservation)

m1u²1 + m2u²2 = m1v²1 + m2v²2

The relationship is the same that the greater mass the greater the impact.

5 0
2 years ago
A constant net force acts on an object. which of the following best describes the object's motion?
Anton [14]
The object<span> is moving with a decreasing acceleration. The </span>object<span> is moving with </span>a constant<span> velocity.</span>
4 0
3 years ago
What is the total energy equation?
netineya [11]
The total energy equation would be Kinetic energy+Potential energy
6 0
3 years ago
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