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3 years ago

An object that crushes under its own weight would fracture _____.

Engineering

1 answer:

marusya05 [52]3 years ago

8 0

Answer:

near the bottom

True

False

Explanation:

If an object crushes due to its weight, it will fracture from bottom first. Young modulus increase will cause buckling easily due to stress. The soft material have nearly zero young modulus. The more the area under moment of inertia there will be less bending causing if difficult to buckle.

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In a Rankine cycle, superheated steam that enters the turbine at 1273.15 K and 1.8 MPa is then expanded to a vapor at 0.1 MPa. W

GrogVix [38]

Answer:

The shaft work generated per kilogram is $-1.3 \frac{MJ}{kg}$

Explanation:

Given:

Temperature $T = 1273.15$ K

Initial Pressure $P_{1} = 1.8$ MPa

Final pressure $P_{2} = 0.1$ MPa

From the table superheated,

$h_{i} = 4635$ $\frac{K J}{Kg}$ and $h_{f} = 2706.54$ $\frac{K J}{Kg}$

Work done by shaft is,

$W = h_{f} - h_{i}$

$W = 2706.54 - 4635$

$W = -1928.46 \frac{kJ}{kg}$

But here efficiency is 0.56,

So work generated per kg is,

Work = $0.56 \times(- 1928.46)$

Work = $-1.3$ $\frac{MJ}{kg}$

Therefore, the shaft work generated per kilogram is $-1.3 \frac{MJ}{kg}$

6 0

3 years ago

A piston–cylinder device contains 15 kg of saturated refrigerant-134a vapor at 280kPa. A resistance heater inside the cylinder w

attashe74 [19]

Answer:

18.77 A

Explanation:

To solve this we use the energy balance equation, that is:

$E_{in}-E_{out}=\Delta E_{sys}\\\\Q_{in}+W_{in}+W_{out}=\Delta U\\\\Q_{in}+W_{in}=\Delta U\\\\But\ W_{in}=Voltage(V)*Current(I)*change\ in\ time(\Delta t)=VI\Delta t,\Delta U=m(h_2-h_1)\\\\Given\ that\ m=15kg,V=110\ V,\Delta t=6\ min = (6*60\ s)=360\ s,Q_{in}=20.67\ kJ/kg*15\ kg=310.05\ kJ=310050\ J\\\\From\ table: At\ P_1=280kPa, h_1=249.71\ kJ/kg=249710\ J/kg;At\ P_2=280kPa \ and\ T_1=75^oC,P_2=319.95\ kJ/kg=319950\ J/kg\\\\Substituting:\\\\310500+(110*360*I)=15(319950-249710)\\\\$

$39600I=1053600-310500\\\\39600I=743100\\\\I=18.77\ A$

3 0

3 years ago

A car is moving at 68 miles per hour. The kinetic energy of that car is 5 × 10 5 J.How much energy does the same car have when i

Blababa [14]

Answer:

The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

Explanation:

Given the data in the question;

Initial velocity v₁ = 68 miles per hour = 30.398 meter per seconds

let mass of the car be m

kinetic energy of that car is 5 × 10⁵ J

E₁ = $\frac{1}{2}$ mv²

we substitute

5 × 10⁵ = $\frac{1}{2}$ × m × ( 30.398 )²

5 × 10⁵ = m × 462.019

m = 5 × 10⁵ / 462.019

m = 1082.2065 kg

Now, Also given that; v₂ = 97 miles per hour = 43.362 meter per seconds

E₂ = $\frac{1}{2}$ mv₂²

we substitute

E₂ = $\frac{1}{2}$ × 1082.2065 × ( 43.362 )²

E₂ = $\frac{1}{2}$ × 1082.2065 × 1880.263

E₂ = 1.017 × 10⁵ J

Therefore, The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

6 0

3 years ago

scrapers are used to haul dirt from a borrow pit to the cap of a landfill. the estimated cycle time for the scrapers is 9.5 minu

ladessa [460]

Answer is: 12.8 because when you multiply it by the 2nd power of 8 then the scraper equals to be 12.8 in height and that’s how much each scraper requires to operate :)

7 0

3 years ago

What are the basic steps in the operation of a solar cell?

kati45 [8]

Answer:

Light is absorbed and knocks electrons loose. Loose electrons flow, creating a current. The current is captured and transferred to wires.

7 0

3 years ago