Answer:
a) 107.1875 Hz
b) 214.375 Hz
c) 321.5625 Hz
Explanation:
L = length of the open organ pipe = 1.6 m
v = speed of sound = 343 m/s
f = fundamental frequency
fundamental frequency is given as
inserting the values
Hz
b)
first overtone is given as
f' = 2f
f' = 2 (107.1875)
f' = 214.375 Hz
c)
first overtone is given as
f'' = 3f
f'' = 3 (107.1875)
f'' = 321.5625 Hz
<u>Answer:</u>
<em>Thunderbird is 995.157 meters behind the Mercedes</em>
<u>Explanation:</u>
It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird decided to take a pit stop and slows down for 250 m. She spent 5 seconds in the pit stop.
Here final velocity
initial velocity distance
Distance covered in the slowing down phase =
The car is in the pit stop for 5s
After restart it accelerates for 350 m to reach the earlier velocity 71 m/s
total time=
Distance covered by the Mercedes Benz during this time is given by
Distance covered by the Thunderbird during this time=
Difference between distance covered by the Mercedes and Thunderbird
=
Thus the Mercedes is 995.157 m ahead of the Thunderbird.