Answer:
{x = 2 , y = -2
Step-by-step explanation:
Solve the following system:
{y = 4 - 3 x | (equation 1)
{y = x/2 - 3 | (equation 2)
Express the system in standard form:
{3 x + y = 4 | (equation 1)
{-x/2 + y = -3 | (equation 2)
Add 1/6 × (equation 1) to equation 2:
{3 x + y = 4 | (equation 1)
{0 x+(7 y)/6 = (-7)/3 | (equation 2)
Multiply equation 2 by 6/7:
{3 x + y = 4 | (equation 1)
{0 x+y = -2 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 6 | (equation 1)
{0 x+y = -2 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 2 | (equation 1)
{0 x+y = -2 | (equation 2)
Collect results:
Answer: {x = 2 , y = -2
Answer:
6 is in ten place and its place value is 60, 3 is in ones place and its place value is 3.
Answer:
Hello!
After reading the question you have provided I have come up with the correct numerical expression:
4x5-1
Step-by-step explanation:
To come up with this solution you need to keep in mind some of the terminoloy being used.
The word "subtract" comes from the action of subtraction
The word "product" comes from the action of multiplication
Thus, using those terminologies correctly, you can then deduce that when the question says "the product of 4 and 5" means "multiplying 4 and 5 together".
So you get the first part being 4x5
Then, you add in the last part of "subract 1" from the "product of 4 and 5":
4x5-1
<em>Remember to keep in mind the rule of "PEMDAS"</em>
You always need to keep the multiplication portion of the equation in front of any subtraction, or addition in any given equation.
Which group of numbers is listed from least to greatest? -8, |-5|, -4, |3|, 6 |-6|, -4, |-2|, -1, 0 -4, |-2|, |3|, 5, |-7| -6, |
Anika [276]
I can’t help you because i can’t distinguish the groups
Answer:
The answer is 66 ways .
Step-by-step explanation:
You have to use <u>Combination</u> because it says choosing 10 out of 12 as the position is not important :
12C10 = 66 ways of arrangements
