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guapka [62]
3 years ago
8

Algebra: simplify 4y-6(5z-2y)-2z

Mathematics
2 answers:
gladu [14]3 years ago
6 0

Answer:

16y−32z

Step-by-step explanation:

:D

bagirrra123 [75]3 years ago
4 0

Answer:

16y−32z

Step-by-step explanation:

multiply the like terms

subtract and add like terms

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Write the equation of the line in fully simplified slope-intercept form.
Amiraneli [1.4K]
Y=2/3x-2

because the slope is 2/3 and y-intercept is -2
5 0
3 years ago
HELP! 10 points!!
Akimi4 [234]

Answer:

A: E = 0.05t +56

B: $73.50

C: $60.05

Step-by-step explanation:

A) I'll just explain the equation in one go

Equation: E = 0.05t + 56

0.05 - This is meant to represent the 5% of tips

5% = 5/100

5/100 = 0.05

56 - This is a set value that has been established as a constant, thus it simply needs to be added to the 5%

B+C) Since we already have the equation set up, we just need to plug in the variable, t.

B) E = 0.05(350) + 56

= 17.5 + 56

= 73.50

C) E = 0.05(81) + 56

= 4.05 + 56

= 60.05

Hope that does something to help, even though this was posted a while ago

6 0
3 years ago
System of equations <br> 5x+y=7<br> 20x+2=y
KIM [24]
Dependent

The general form for a pair of linear equations in two variables x and y is
and

----- (1)
----- (2)
Comparing equations 1 and 2 with the general form of equation to write their co-efficient,

Compare the ratio,

If , then the pair of linear equations has exactly one solution.
So, it said to be consistent.
7 0
4 years ago
4x^2 = 16 please show work
disa [49]
4x²=16
x²=16/4
x²=4
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5 0
4 years ago
The temperature on a mountain peak was 7 degreesFahrenheit (F) at 6:00 p.m. By 8:00 p.m., thetemperature had dropped to 0F. If t
VashaNatasha [74]

Given:

The temperature on a mountain peak was 7°F at 6:00 p.m.

By 8:00 p.m., the temperature had dropped to 0°F.

To find:

The temperature at 11:00 p.m. if the temperature continued to drop at about the same rate.

Solution:

Time between 6:00 p.m. to 8:00 p.m. is 2 hours.

Change in temperature in 2 hours is -7°F.

Change in temperature in 1 hours is -\dfrac{7}{2}^\circF.

Time between 8:00 p.m. to 11:00 p.m. is 3 hours.

Change in temperature in 3 hours is 3\times \dfrac{-7}{2}^\circF, i.e., -\dfrac{21}{2}^\circF.

Now, the temperature at 11:00 p.m is:

0-\dfrac{21}{2}=-10.5

Therefore, the temperature at 11:00 p.m. is -10.5°F.

Note: All options are incorrect.

6 0
3 years ago
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