Answer:
Write the following Quantitiesin scientific notation.
a. 10130 Pa to 2 decimal place
b. 978.15m * s-2 to one decimal place
c 0.000001256 A to3 decimal place
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Answer: a.
b.
c.
Explanation:
Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.
For example : 5000 is written as
a. 10130 Pa to 2 decimal place is written as
b. to 1 decimal place is written as
c. to 3 decimal places is written as
Explanation:
Answer:
If gravity on Earth is increased, this gravitational tugging would have influenced the moon's rotation rate. If it was spinning more than once per orbit, Earth would pull at a slight angle against the moon's direction of rotation, slowing its spin. If the moon was spinning less than once per orbit, Earth would have pulled the other way, speeding its rotation.
Answer:
86.6, 45°
Explanation:
The diagram explains better.
Using vector component method:
We find the x and y components of the vectors :
For the first:
A = -50cos(0)i + 50sin(0)j
A = -50i
For the second:
B = -50cos(60)i + 50sin(60)j
B = -25i + 43.3j
The resultant vector is :
R = A + B
R = -50i - 25i + 43.3j
R = -75i + 43.3j
The magnitude is:
R = [(-75)² + (43.3)²]^½
R = 86.6m
The angle is
tanθ = (50/50) = 1
θ = 45°
'A' and 'C' are exactly the same circuit, except the voltmeter's terminals are flipped.
'A' is the correct way to hook everything up.
If you start at the positive terminal of the battery, and follow the flow of current through the circuit and around to the negative terminal, you're following the path where the voltage gets lower and lower and lower all the way.
So each time you come to any device in the circuit ... whether it's a resistor or a meter ... you would be hitting the positive side of it first, and then the voltage where you come out on the other side of it would be lower.
So the left side of the resistor is more positive, and the right side is more negative. The voltmeter is connected correctly in 'A', but it's backwards in 'C'. If you connect the voltmeter like in 'C' and turn things on, the voltmeter will try to go <em>down</em> from zero. You can't read the number on it, and It's possible that the voltmeter might be damaged.
Answer: a) 2.5 * 10^14, b) t = 1.2*10^-8 s, c) F = 2.2775 * 10^-15 N
Explanation: Since it starts from rest, initial velocity = 0, final velocity (v) = 3*10^6 m/s, distance covered (s) = 1.80cm = 1.80/100 = 0.018m
Since the force on the electron is constant, it acceleration will be constant too thus making newton's laws of motion valid.
Question a)
To get the acceleration, we use the formulae that
v² = u² + 2as
But u = 0
v² = 2as
(3*10^6)² = 2*a*(0.018)
9* 10^12 = 0.036*a
a = 9 * 10^12 / 0.036
a = 250 * 10^12
a = 2.5 * 10^14 m/s².
Question b)
To get the time, we use
v = u + at
But u = 0
v = at
3*10^6 = 2.5 * 10^14 * t
t = 3*10^6 / 2.5*10^14
t = 1.2*10^-8 s
Question c)
To get the force, we use the formulae below
F = ma
F = 9.11*10^-31 * 2.5 * 10^14
F = 22.775 * 10^-17
F = 2.2775 * 10^-15 N
