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4 years ago

When a potential difference of 20 V is applied to a given wire, it conducts 0.25 A of current.?

1 answer:

4 0

Well if the wire has an insane length or is made out of a high resistance material. But, you're probably looking for a resistor : R = U / I ; R = 20V / 0.25A

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Two planets X and Y travel counterclockwise in circular orbits about a star, as seen in the figure. The radii of their orbits ar

Korvikt [17]

By 272.7 degrees angle has planet Y rotated through during this time.

<h3 /><h3>What is Kepler's 3rd law?</h3>

The cubes of the semi-major axes of the planets' orbits are precisely proportional to the squares of the planets' orbital periods. According to Kepler's Third Law, as an orbiting planet's radius rises, so does the time of its orbit around the Sun.

Using Kepler's 3rd law, which says that the period of any planet's orbit squared is proportional to the radius of the orbit cubes, we can establish that

(period X / period Y)^2 = (radius X / radius Y)^3

(period X / period Y)^2 = 2^3 = 8

take sq root

period X / period Y = √8 = 2.82≅ 3

this means it takes planet X 2.82≅ 3 times longer to go through one orbit... so planet Y travels 2.82≅ 3 times as far (in its orbit...) as planet X!

This means...

planet Y travels 3 * 90.9 = 272.7 degrees

to learn more about Kepler's 3rd law go to - brainly.com/question/16705471

#SPJ4

7 0

2 years ago

On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const

IceJOKER [234]

Answer:

Explanation:

Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:

$x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2} (1)$

Since the car starts from rest, v₀ =0.
We know the value of t = 5 sec., but we need to find the value of a.
Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:

$a_{c} =\frac{v_{fc}}{t} = \frac{20m/s}{5s} = 4 m/s2 (2)$

Replacing a and t in (1):

$x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2} = \frac{1}{2}*a*t^{2} = \frac{1}{2}* 4 m/s2*(5s)^{2} = 50.0 m. (3)$

Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:

$a_{t} =\frac{-v_{to}}{t} = \frac{-20m/s}{10s} = -2 m/s2 (4)$

Replacing v₀, at and t in (1), we have:

$x_{ft} = 20m/s*10.0s + \frac{1}{2}*(-2 m/s2)*(10.0s)^{2} = 200m -100m = 100.0m (5)$

Therefore, as the truck travels twice as far as the car, the right answer is a).

7 0

3 years ago

For aerodynamic reasons, nearly all modern aircraft feature at leastone large vertical stabilizer. The B-2 "stealth" bomber pict

andrew-mc [135]

Answer:

Answer:

The reason why the B-2 "stealth" bomber has no vertical fins (or stabilizers) at all, is because by design, the vertical fins are not required to provide stability; the stability for yaw movement is provided through a computer that controls the B-2 stealth bomber; hence the B-2 stealth bomber does not need a vertical stabilizer in order to fly.

6 0

3 years ago

I dont get ohm's law

nata0808 [166]

Answer:

Ohms law state that the current I flowing through a metallic conductor is directly proportional to the potential difference V across its end, provided that all physical condition are kept constant i.e temperature

Explanation:

that is, V varies directly to I

Where,

V= potential difference in volt and

I = current in Ampere (A)

therefore,

V= IR and R is measured in ohm

8 0

4 years ago

What does weighing less on the moon mean for astronauts on the moon?

AnnyKZ [126]

Answer:

Isaac Newton discovered that as an object's mass increases, the gravitational attraction of that object increases. Thus, the gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon.

hope this helps!

5 0

2 years ago