Answer:
-26.125 kj
Explanation:
Given data:
Mass of water = 250.0 g
Initial temperature = 30.0°C
Final temperature = 5.0°C
Amount of energy lost = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 5.0°C - 30.0°C
ΔT = -25°C
Specific heat of water is 4.18 j/g.°C
Now we will put the values in formula.
Q = m.c. ΔT
Q = 250.0 g × 4.18 j/g.°C × -25°C
Q = -26125 j
J to kJ
-26125 j ×1 kj /1000 j
-26.125 kj
It may be unreliable because it might mess something up from the speed.
Answer: Molecules only speed up when given energy, such as heating. When you heat water enough, it will boil and turn into water vapor. So, therefore, if water's molecules speed up, it will go into the gas phase
Explanation: As that liquid water is further heated, it evaporates and becomes a gas—water vapor. These changes between states (melting, freezing, and evaporating) happen because as the temperature either increases or decreases, the molecules in a substance begin to speed up or slow down.
Hope this helps! ^w^
Atomic mass W = 183.84 u.m.a
183.84 g ----------- 6.02x10²⁴ atoms
?? g ---------------- 2.1x10²⁴ atoms
2.1x10²⁴ x 183.84 / 6.02x10²⁴ =
3.860x10²⁶ / 6.02x10²⁴ = 641.30 g
hope this helps!
Answer:
atomic mass ( N =14 , H = 1×3 that means 14+3=17
340gram×17gram / mole
=5780mole
atomic mass ( H= 1×2 ,O= 16 =16+2 =18
90gram×18gram /mole
=1620mole
I think 340g ammonia (NH3)
