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slega [8]
2 years ago
5

A 250–g piece of gold is at 19 °C. 5.192 kJ of energy is added to it by heat. The specific heat of gold is 129 J/(kg·°C). Calcul

ate its final temperature.
We heat a 25–g sample of metal from 10 °C to 100 °C. 1.082 kJ of energy is added to it by heat. Calculate
the specific heat of the metal.
Physics
1 answer:
algol [13]2 years ago
7 0

Answer:

A. DT is given by Q= MCs DT

m = mass of the substances

Cs= is it's specific heat capacity

Ck= <u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>Q</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

Mk ×DTk

=<u>2</u><u>5</u><u>0</u><u> </u><u>×</u><u> </u><u>9</u><u> </u><u>×</u><u> </u><u>5</u><u> </u><u> </u>

129

=Dt = 180.1085271

answer is 180degree C.

Explanation:

B. = <u>2</u><u>5</u><u>×</u><u>1</u><u>0</u> ×100

1.082

=<u>2</u><u>5</u><u>0</u><u>0</u>

1.082

= 23105.360 g/kj.

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A 1000kg truck is moving at a velocity of 4m/s what is it's momentum?
Alona [7]

Answer:

4000 kg m/s

Explanation:

<u><em>p=mv</em></u>

  • p = momentum in kg m/s
  • m = mass in kg
  • v = velocity in m/s

substitute values into the formula above to get:

p=1000x4

<u><em>p=4000 kg m/s</em></u>

6 0
2 years ago
A 30 kg buzzard is sitting on a cable. The cable is attached to two poles 25
sertanlavr [38]

Answer:

T1 = 675 [N] ; T2 = 707.5 [N]

Explanation:

To solve this problem we must draw a free body diagram, where the bird is located, the posts and distances mentioned.

In the attached image we can see the free body diagram with different forces, angles and distances.

By conducting a distance analysis we can find the angles on both sides of the rope relative to the horizontal.

Then we perform a force analysis on the X-axis and the y-axis in order to find the two equations we need to find the stresses in the cables (T1 & T2)

6 0
2 years ago
Describe a situation in which gravity causes a change in velocity
Katarina [22]
That's what happens whenever anything is dropped or falls.
-- a roller coaster leaves the top of a hill
-- a pencil rolls off the desk
-- the cat jumps off the top of the refrigerator
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5 0
3 years ago
A train car with mass m1 = 590 kg is moving to the right with a speed of v1 = 7.3 m/s and collides with a second train car. The
loris [4]

Answer:

4307 kg.m/s

Explanation:

Momentum is the product of mass and velocity of an object.

p=mv where p is momentum, m is mass of the object and v is the velocity.

Taking right direction as positive, the initial momentum of the first train car will be 590*7.3=4307 kg.m/s

We know that from law of conservation of linear momentum, the sum of initial momentum equals the sum of final momentum

8 0
3 years ago
A two-liter bottle is one-fourth full of water and three-quarters full of air. The air in the bottle has a gage pressure of 340
Fantom [35]

Answer:

The value is     P_G  =  2.925 *10^{5} \  Pa

Explanation:

From the question we are told that

   The  volume of the bottle is  v  =  2 \  L  =  2 *  10^{-3} \  m^3

   The gauge pressure of the air is P_g  =  340 \  kPa  =  340 *10 ^{3}  \  Pa

   

Generally the volume of air before the bottle is turned upside down is  

      V_a  =  \frac{3}{4}  * V

       V_a  =  \frac{3}{4}  *  2 *10^{-3}

       V_a  =  0.0015 \  m^3 }

Generally the volume air when the bottle is turned upside-down is

      V_u  =  \frac{5}{6}  *  2 *10^{-3}

       V_u  =  0.00167 \  m^3

From the the mathematical relation of adiabatic process we have that

     P_g *  V_a^r  =  P_G *  V_u^r

Here r is a constant with  a value  r =  1.4

So

      340 *10 ^{3}  *  0.0015^{1.4}  =  P_G *  0.00167^{1.4}

        P_G  =  2.925 *10^{5} \  Pa

3 0
2 years ago
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