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Makovka662 [10]
3 years ago
9

IF YOU WANT POINTS GET SOME HERE

Mathematics
2 answers:
Murrr4er [49]3 years ago
6 0

Answer:

Yo thanks a lot May God bless you ❤

kirill [66]3 years ago
5 0

Answer:

thank you

Step-by-step explanation:

:P

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Find the cube root of 19683 by prime factorization method. Show steps.
ANTONII [103]

Answer:

  • 27

Step-by-step explanation:

<u>Given number:</u>

  • 19683

<u>Prime factors of 19683:</u>

  • 19683 = 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 × 3 = 3^9

<u>Cube root:</u>

  • ∛19683 = ∛3^9 = 3^3 = 27
3 0
3 years ago
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Identify the irrational sum(s). Select all that apply. (My second and last question!)
SashulF [63]
I believe is A :)
You are welcome
4 0
3 years ago
Find the vertical and horizontal asymptotes, domain, range, and roots of f (x) = -1 / x-3 +2.
gladu [14]

Answer:

Vertical asymptote: x=3

Horizontal asymptote: f(x) =2

Domain of f(x) is all real numbers except 3.

Range of f(x) is all real numbers except 2.

Step-by-step explanation:

Given:

Function:

f (x) = -\dfrac{1 }{ x-3} +2

One root, x = 3.5

To find:

Vertical and horizontal asymptote, domain, range and roots of f(x).

Solution:

First of all, let us find the roots of f(x).

<em>Roots of f(x) means the value of x where f(x) = 0</em>

0= -\dfrac{1 }{ x-3} +2\\\Rightarrow 2= \dfrac{1 }{ x-3}\\\Rightarrow 2x-2 \times 3=1\\\Rightarrow 2x=7\\\Rightarrow x = 3.5

One root, x = 3.5

Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) \rightarrow \infty

For all, other values of x , f(x) is defined.

Hence, Domain of f(x) is all real numbers except 3.

Range of f(x) i.e. the values that are possible output of the function.

f(x) = 2 is not possible in this case because something is subtracted from 2. That something is \frac{1}{x-3}.

Hence, Range of f(x) is all real numbers except 2.

Vertical Asymptote is the value of x, where value of f(x) \rightarrow \infty.

-\dfrac{1 }{ x-3} +2 \rightarrow \infty

It is possible only when

x-3=0\\\Rightarrow x=3

\therefore vertical asymptote: x=3

Horizontal Asymptote is the value of f(x) , where value of x \rightarrow \infty.

x\rightarrow \infty \Rightarrow \dfrac{1 }{ x-3} \rightarrow 0\\\therefore f(x) =-0+2 \\\Rightarrow f(x) =2

\therefore Horizontal asymptote: f(x) =2

Please refer to the graph of given function as shown in the attached image.

5 0
3 years ago
Luis is standing on a street in New York City
horrorfan [7]

Answer:

cos 30° =767.6/hypotenus

(make h the subject of the formular)

h = 767.6/cos 30°

h =767.6/0.154

h =4,985

approximately 5,000

4 0
3 years ago
(◞ ‸ ◟) PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP ≧﹏≦
Natasha_Volkova [10]

6. Classify the angle as acute, right, obtuse, or straight.

A. obtuse

B. acute

C. straight

D. right​

(THE ANSWER IS OBTUSE ANGLE)

An Obtuse Angle Is what your looking at right now. Its angle is bigger than 90 degree.

A Acute angle is lower than 90 degree which tends to make something looking like the “<” “>” sign.

And straight angle is just a straight line (No kidding)

A right angle is justs a L shape sign. The corner of the L 90 degree

3 0
3 years ago
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