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2 years ago

Determine whether the interference is constructive or destructive at each location indicated.

Physics

1 answer:

OlgaM077 [116]2 years ago

6 0

Answer:

A. Constructive

B. Destructive

C. Destructive

D. Constructive

Explanation:

Constructive interference takes place at locations along the path of two superposed waves where the waves are in phase such that a high or low point of one of the waves corresponds with a high or low point of the other wave which gives a resulting wave amplitude which is the sum of the amplitudes of the individual waves

Destructive interference takes place at locations along the path of two superposed waves where one wave is out of phase with the other wave such that a high or low point of one of the waves coincides with a low or high point of the other wave respectively thereby cancelling the effect of the other wave and giving a resulting wave that has an amplitude which is the difference in the amplitudes of the individual waves

Therefore;

At point A, the peak of each wave partially coincides resulting in constructive interference

At point B, the peak of the blue wave and the trough of the red wave partially coincides resulting in destructive interference

At point C, the through of the blue wave and the peak of the back wave partially coincides resulting in destructive interference

At point D, the trough of each wave partially coincides resulting in constructive interference.

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gavmur [86]

Answer:

m = 9.6 g

Explanation:

Thermal energy given to helium gas at constant volume is given as

$Q = nC_v \Delta T$

so here we have

$C_v = \frac{3}{2}R$

$n = moles$

$n = \frac{2}{4} = 0.5$

so we have

$Q = \frac{3}{2}R(0.5)\Delta T$

now we know that

for oxygen gas we have

$C_v = \frac{5}{2}R$

for same amount of heat we have

$Q = nC_v \Delta T'$

$\frac{3}{2}R(0.5)\Delta T = \frac{m}{32} (\frac{5R}{2}) \Delta T$

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$m = 9.6 g$

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2 years ago

Which research method uses questionnaires to collect information about the participants in a study?

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2 years ago

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A 1,492.3-kg airplane travels down the runway. Each of its four engines provides a force of

Fittoniya [83]

The acceleration of the air plane is $3.879 \mathrm{m} / \mathrm{s}^{2}$

Explanation:

Given:

The mass of the air plane = 1492.3 kg

Force of each four engine = 1447.5 N

So, the total force of four engines can be calculated as = 4(1447.5) = 5790 N

The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

$\text {Force }(F)=m \times \text { acceleration }(a)$

The above equation can be written as below to find acceleration,

$a=\frac{F}{m}$

Now. Substitute the given values, we get,

$a=\frac{5790}{1492.3}=3.879 \mathrm{m} / \mathrm{s}^{2}$

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2 years ago

A 3.91 kg cart is moving at 5.7 m/s when it collides with a 4 kg cart which was at rest. They collide and stick together.

Nesterboy [21]

Answer:

The velocity after the collision is 2.82 m/s

Explanation:

Law Of Conservation Of Linear Momentum

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is

P=mv.

If we have a system of two bodies, then the total momentum is the sum of the individual momentums:

$P=m_1v_1+m_2v_2$