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lisov135 [29]
3 years ago
5

How many grams does f Cacl2 should be dissolved in 750.0 mL of water to make a 0.100 M solution Cacl2

Chemistry
1 answer:
AVprozaik [17]3 years ago
6 0

Answer:

8.324 g

Explanation:

First we <u>convert 750.0 mL into L</u>:

  • 750.0 mL / 1000 = 0.750 L

Then we <u>calculate the required number of moles of CaCl₂</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / liters
  • Molarity * liters = moles
  • 0.100 M * 0.750 L = 0.075 mol

Finally we <u>convert 0.075 moles of CaCl₂ into grams</u>, using its <em>molar mass</em>:

  • 0.075 mol * 110.98 g/mol = 8.324 g
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Answer:

178.98 sq. feet

Explanation:

The path and the garden has been shown in the figure below. The green area is the garden and the area in brown is the path.

It has been given that,

Radius of garden = 8 feet

So, the area of garden = 3.14 × 8 × 8 = 200.96 sq. feet

The total radius of the land including garden and path = 8 + 3 = 11 feet

So, the total are of land including garden and path = 3.14 × 11 × 11 = 379.94 sq. feet

So, the area of path = Total area of the land - area of garden

Area of path = 379.94 - 200.96 = 178.98 sq. feet

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3 years ago
What are some ways to eliminate waste
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Answer:

use following methods

Explanation:

  • Recycling the waste
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3 years ago
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A beta particle is an electron and it has a -1 charge and zero mass.

Beta decay by emitting an electron is called as β⁻ decay. When this happens, a neutron of the element converts into a proton by emitting an electron. Hence, the mass of daughter nucleus is same as parent atom but atomic number/number of protons is higher by 1 than atomic number of parent atom.

In a β⁻ decay, the symbol is used as ₋₁⁰β or ₋₁⁰e.
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3 years ago
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Which is true about the dissolving process in water?
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Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
mamaluj [8]

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

2SO_2 + O_2 \to 2SO_3

The I.C.E table can be represented as:

                     2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,  

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction 2SO_2 + O_2 \to 2SO_3 = 0.8325;

If we want to find:

SO_2 + \dfrac{1}{2}O_2 \to SO_3

Then:

K_c = (0.8325)^{1/2}

\mathbf{K_c = 0.912}

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

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