All categories

3 years ago

How many grams does f Cacl2 should be dissolved in 750.0 mL of water to make a 0.100 M solution Cacl2

Chemistry

1 answer:

AVprozaik [17]3 years ago

6 0

Answer:

8.324 g

Explanation:

First we convert 750.0 mL into L:

750.0 mL / 1000 = 0.750 L

Then we calculate the required number of moles of CaCl₂, using the definition of molarity:

Molarity = moles / liters

Molarity * liters = moles

0.100 M * 0.750 L = 0.075 mol

Finally we convert 0.075 moles of CaCl₂ into grams, using its molar mass:

0.075 mol * 110.98 g/mol = 8.324 g

You might be interested in

How do I find the charge of the ion with this info? Please help!

luda_lava [24]

The answer would be c

7 0

3 years ago

What is the average atomic mass of the following isotopic mixture - 42.10 g/mole- 93.50%; 48.30 g/mole 6.200%; 50.40 g/mole - 0.

bazaltina [42]

Answer:

40.03g/mole

Explanation:

Given parameters:

Mass = 42.10 g/mole and abundance = 93.50%

Mass = 8.30 g/mole and abundance = 6.200%

Mass = 50.40 g/mole and abundace = 0.3000%

Find;

Average atomic mass = ?

Solution:

Average atomic mass = sum (mass x abundance)

Average atomic mass = ( $\frac{93.50}{100} x 42.1$ ) + ( $\frac{6.2}{100}$ x 8.3) + ( $\frac{0.3}{100} x 50.4$ )

= 39.36g/mole + 0.52g/mole + 0.15g/mole

= 40.03g/mole

8 0

3 years ago

If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how m

lara [203]

Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.

Explanation : As a single egg cell has an approximately diameter of 100 μm.

We can use this formula to calculate area of the cell membrane;

A = π $(100)^{2} / 4$ ;

We can take π as 3.14 and we get;

A = 3.14 X $(100)^{2} / 4$

Soving we get;

A = 7850 μ $m^{2}$

Here we have to calculate the amount of dye molecules which will be needed for 10 fluorescent molecules / μ $m^{2}$ but;

here 1 μ $m^{2}$ = 7850 μ $m^{2}$ dye molecules.

Therefore, 10 fluorescent molecules will need;

7850 X 10 = 78500 molecules of dye.

Therefore, the answer is 78500 molecules of dye.

6 0

3 years ago

What is the nature of this chlorine ion?

PIT_PIT [208]

As chlorine has seven electrons in its outer most shell so to complete its octet it has to gain an electron and when it gain an electron it will become an anion that is negatively charged
so in my opinion and what a conclude is that the option B is correct for the above statement

3 0

3 years ago

Read 2 more answers

At 400 K oxalic acid decomposes according to the reaction:H2C2O4(g)→CO2(g)+HCOOH(g)In three separate experiments, the intial pre

padilas [110]

Answer:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

Explanation:

For the reaction:

H₂C₂O₄(g) → CO₂(g) + HCOOH(g)

At t = 0, the initial pressure is just of H₂C₂O₄(g). At t= 20000 s, pressures will be:

H₂C₂O₄(g) = P₀ - x

CO₂(g) = x

HCOOH(g) = x

P at t=20000 is:

P₀ - x + x + x = P₀+x. That means P at t=20000s - P₀ = x

For 1st point:

x = 92,8-65,8 = 27

Pressure of H₂C₂O₄(g) at t=20000s: 65,8-27 = 38,8

2nd point:

x = 130-92,1 = 37,9

H₂C₂O₄(g): 92,1 - 37,9 = 54,2

3rd point:

x = 157-111 = 46

H₂C₂O₄(g): 111-46 = 65

Now, as the rate law is :

v = k P[H₂C₂O₄]

Based on integrated rate law, k is:

(- ln P[H₂C₂O₄] + ln P[H₂C₂O₄]₀) / t = k

1st point:

k = 2,64x10⁻⁵

2nd point:

k = 2,65x10⁻⁵

3rd point:

k = 2,68x10⁻⁵

The averrage of this values is:

k = 2,66x10⁻⁵

That means law is:

v = 2,66x10⁻⁵ P[H₂C₂O₄]

I hope it helps!

4 0

3 years ago