3 years ago

How many grams does f Cacl2 should be dissolved in 750.0 mL of water to make a 0.100 M solution Cacl2

Chemistry

1 answer:

AVprozaik [17]3 years ago

6 0

Answer:

8.324 g

Explanation:

First we convert 750.0 mL into L:

750.0 mL / 1000 = 0.750 L

Then we calculate the required number of moles of CaCl₂, using the definition of molarity:

Molarity = moles / liters

Molarity * liters = moles

0.100 M * 0.750 L = 0.075 mol

Finally we convert 0.075 moles of CaCl₂ into grams, using its molar mass:

0.075 mol * 110.98 g/mol = 8.324 g

You might be interested in

A cylinder of compressed gas has a volume of 350 ml and a pressure of 931 torr. What volume in Liters would the gas occupy if al

hodyreva [135]

Answer:

$0.384\ \text{L}$

Explanation:

$P_1$ = Initial pressure = 931 torr = $931\times \dfrac{101.325}{760}=124.12\ \text{kPa}$

$P_2$ = Final pressure = 113 kPa

$V_1$ = Initial volume = 350 mL

$V_2$ = Final volume

From the Boyle's law we have

$P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{124.12\times 350}{113}\\\Rightarrow V_2=384.44\ \text{mL}=0.384\ \text{L}$

The volume the gas would occupy is $0.384\ \text{L}$ .

3 0

3 years ago

5.36 liters of nitrogen gas are at STP. What would be the new volume if we increased the moles from 3.5 moles to 6.0 moles?

Aleksandr [31]

Answer:

$V_2=9.20L$

Explanation:

Hello there!

In this case, according to the given STP (standard pressure and temperature), it is possible for us to realize that the equation to use here is the Avogadro's law as a directly proportional relationship between moles and volume:

$\frac{V_2}{n_2}= \frac{V_1}{n_1}$