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ddd [48]
3 years ago
7

Show how you would synthesize each compound from benzene, toluene, or phenol using the following reactions: Choose the starting

material from the drop-down list Enter the number(s) of the desired reactions in the order that you wish to use them without commas between If a reaction is used more than once, enter its number each time you wish to use it Compound 1: 2-amino-4-bromophenol Starting material: Reaction(s): Compound 2: 5-chloro-2-methylbenzenesulfonic acid Starting material: Reaction(s):

Chemistry
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

1. Phenol

  Amination and bromination

2. Toluene

Sulfonation and chlorination

Explanation:

In this question, we are tasked with with stating the starting materials and the kind of reaction needed for the production of the particular compound in question.

We proceed as follows;

<u>COMPOUND 1</u>

<u>Name</u>; <em>2-amino-4-bromophenol</em>

<u>Starting materials;</u> Phenol

<u>Reactions; </u>Amination and Halogenation(Bromination to be specific)

To produce 2-amino-bromophenol, two reactions are incorporated on the phenol starting product. Amination is carried out using aminating reagent such as hydroxylamine through electrophilic substitution while halogenation is  carried out using bromine water

<u>COMPOUND 2</u>

<u>Name;</u> 5-chloro-2-methylbenzenesulfonic acid

<u>Starting materials</u>; Toluene

<u>Reactions;</u> Sulphonation and Halogenation (Bromination)

To produce 5-chloro-2-methylbenzenesulfonic acid, two reactions are incorporated on the toluene starting product. Chlorination is carried out first, while sulfonation using sulfuric acid is carried out afterwards

PLEASE CHECK ATTACHMENT FOR REACTION SCHEMA

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How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?
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Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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  • H₂: 3 moles
  • NH₃: 2 moles

The molar mass of the compounds is:

  • N₂: 14 g/mole
  • H₂: 2 g/mole
  • NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • N₂: 1 mole ×14 g/mole= 14 grams
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  • NH₃: 2 moles ×17 g/mole=34 grams

<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}

<u><em>moles of NH₃= 5.33 moles</em></u>

Then, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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