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ddd [48]
4 years ago
7

Show how you would synthesize each compound from benzene, toluene, or phenol using the following reactions: Choose the starting

material from the drop-down list Enter the number(s) of the desired reactions in the order that you wish to use them without commas between If a reaction is used more than once, enter its number each time you wish to use it Compound 1: 2-amino-4-bromophenol Starting material: Reaction(s): Compound 2: 5-chloro-2-methylbenzenesulfonic acid Starting material: Reaction(s):

Chemistry
1 answer:
Phantasy [73]4 years ago
6 0

Answer:

1. Phenol

  Amination and bromination

2. Toluene

Sulfonation and chlorination

Explanation:

In this question, we are tasked with with stating the starting materials and the kind of reaction needed for the production of the particular compound in question.

We proceed as follows;

<u>COMPOUND 1</u>

<u>Name</u>; <em>2-amino-4-bromophenol</em>

<u>Starting materials;</u> Phenol

<u>Reactions; </u>Amination and Halogenation(Bromination to be specific)

To produce 2-amino-bromophenol, two reactions are incorporated on the phenol starting product. Amination is carried out using aminating reagent such as hydroxylamine through electrophilic substitution while halogenation is  carried out using bromine water

<u>COMPOUND 2</u>

<u>Name;</u> 5-chloro-2-methylbenzenesulfonic acid

<u>Starting materials</u>; Toluene

<u>Reactions;</u> Sulphonation and Halogenation (Bromination)

To produce 5-chloro-2-methylbenzenesulfonic acid, two reactions are incorporated on the toluene starting product. Chlorination is carried out first, while sulfonation using sulfuric acid is carried out afterwards

PLEASE CHECK ATTACHMENT FOR REACTION SCHEMA

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Calculate the concentration of formate in a 100mm solution of formic acid at ph 4.15. The pka for formic acid is 3.75
MissTica

The molarity of formic acid is 100 mM or 100\times 10^{-3}M. The dissociation reaction of formic acid is as follows:

HCOOH\leftrightharpoons HCOO^{-}+H^{+}

The expression for dissociation constant of the reaction will be:

K_{a}=\frac{[HCOO^{-}][H^{+}]}{[HCOOH]}

Rearranging,

[HCOO^{-}]=\frac{K_{a}[HCOOH]}{[H^{+}]}

Here, pH of solution is 4.15 thus, concentration of hydrogen ion will be:

[H^{+}]=10^{-pH}=10^{-4.15}=7.08\times 10^{-5}M

Similarly, pK_{a}=3.75 thus,

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Answer:

8. the answer is B.

9. the answer is A.

Explanation:

Hello!

8. In this case, by bearing to mind that the limiting reactant is always completely consumed and the excess one remain as a leftover at the end of the reaction, we can also infer that as all the limiting reactant is consumed, it must determine the maximum amount of product as the excess reactant will hypothetically produce a greater mass than expected; thus, the answer to this question is B.

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Best regards!

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