The chemical formula for the compound containing 8.6 mol of sulfur and 3.42 mol of phosphorus is P₂S₅
<h3>How do I determine the formula of the compound?</h3>
From the question given above, the following data were obatined:
- Sulphur (S) = 8.6 moles
- Phosphorus (P) = 3.42 mole
- Chemical formula =?
The chemical formula of the compound can be obtained as follow:
Divide by their molar mass
S = 8.6 / 32 = 0.26875
P = 3.42 / 31 = 0.11032
Divide by the smallest
S = 0.26875 / 0.11032 = 2.44
P = 0.11032 / 0.11032 = 1
Multiply by 2 to express in whole number
S = 2.44 × 2 = 5
P = 1 × 2 = 2
Thus, the chemical formula is P₂S₅
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The correct option is this: SODIUM IS VERY REACTIVE BECAUSE IT DOES NOT HAVE A FULL VALENCE SHELL.
For an atom to attain an octet form, it must have eight electrons in its outermost shell. Elements with eight electrons in their outermost shells are un-reactive. Sodium has only one electron in its outermost shell, this makes it to be very reactive because it is very willing to react with suitable elements in order to become stable.
Answer:
Maintenance of homeostasis usually involves negative feedback loops. These loops act to oppose the stimulus, or cue, that triggers them.
Spore formation is a form of asexual reproduction used by mushrooms and molds.
During budding, the offspring grows from the body of the parent.
Fragmentation is a form of asexual reproduction that must be followed by regeneration.
Explanation:
Asexual reproduction is the type of reproduction where the gamete formation and fusion have no relevance or existence. It functions on the process of somatic cell division via mitosis and the offsprings are identical to their parents.
The spore formation occurs in fungi through sporangia, bursting open to shed spores, forming into a new young ones. Budding occurs out as an outgrowth of the parent and attains maturity and separates. Fragmentation is the process where the parents fall apart into pieces and regeneration follows.
