Answer: 0.013 seconds
Explanation:
Given that
Mass of golf ball = 0.058 kg
Force = 272 N
Velocity = 62.0 m/s
Time taken = ?
Recall that force is the rate of change of momentum per unit time
i.e Force = Change in momentum / Time
i.e Force = (Mass x velocity) / Time
272N = (0.058 kg x 62.0 m/s) / Time
272N = 3.6kgm/s / Time
Time = (3.6kgm/s / 272N)
Time = 0.013 seconds
Thus, the ball was in contact with the club for 0.013 seconds
a) It can dissolve other substances and has high specific heat capacity.
b) Pressure is transferred equally in all directions
c) F=14*0.04/0.02=28 N
d) I'd expect that it will sink cause weight will pull it to the bottom
e) Because the buoyant force is stipulated by difference between pressures in the top and bottom surfaces of a body.
f) Because this force increases in denser liquids:
, where rho is density.
g) Q=Av, where v - speed, A - area. With the same flow rate v=Q/A, so larger area decreases speed and vice versa.
Answer:
71.4583 Hz
67.9064 N
Explanation:
L = Length of tube = 1.2 m
l = Length of wire = 0.35 m
m = Mass of wire = 9.5 g
v = Speed of sound in air = 343 m/s
The fundamental frequency of the tube (closed at one end) is given by

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz
The linear density of the wire is

The fundamental frequency of the wire is given by

The tension in the wire is 67.9064 N
Answer:
19.9 N/m
Explanation:
From the question,
Applying Hook's law
F = Ke.................. Equation 1
Where F = Force on the spring, k = spring constant, e = extension
But the force on the spring is the weight of the mass
Therefore,
mg = ke.................. Equation 2
Where m = mass. g = acceleration due to gravity
make e the subject of the equation
e = mg/e................ Equation 3
Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,
Constant: g = 9.8 m/s²
Substitute these values into equation 3
e = (0.455×9.8)/0.224
e = 19.9 N/m