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uysha [10]
4 years ago
13

20 POINTS PLZ HELP- Describe how two type of land use within your watershed can influence the water quality in Rivers in your ar

ea?
Physics
1 answer:
JulsSmile [24]4 years ago
7 0

Answer:

Pollution Sources & Land Use. Imperviousness & Water Quality ... protect streams, rivers, and ground water, land use practices can be implemented ... In built-up areas with pavement and buildings, little rainfall soaks into the soil Ground water flows slowly into streams, usually over a period of months,

Explanation:

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Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with
Mekhanik [1.2K]

Answer: 0.013 seconds

Explanation:

Given that

Mass of golf ball = 0.058 kg

Force = 272 N

Velocity = 62.0 m/s

Time taken = ?

Recall that force is the rate of change of momentum per unit time

i.e Force = Change in momentum / Time

i.e Force = (Mass x velocity) / Time

272N = (0.058 kg x 62.0 m/s) / Time

272N = 3.6kgm/s / Time

Time = (3.6kgm/s / 272N)

Time = 0.013 seconds

Thus, the ball was in contact with the club for 0.013 seconds

8 0
4 years ago
A. Water has many unique properties. Identify a property of water and explain why this property makes water vital to living orga
rosijanka [135]

a) It can dissolve other substances and has high specific heat capacity.

b) Pressure is transferred equally in all directions

c) F=14*0.04/0.02=28 N

d) I'd expect that it will sink cause weight will pull it to the bottom

e) Because the buoyant force is stipulated by difference between pressures in the top and bottom surfaces of a body.

f) Because this force increases in denser liquids: F_b=\rho gV, where rho is density.

g) Q=Av, where v - speed, A - area. With the same flow rate v=Q/A, so larger area decreases speed and vice versa.

8 0
3 years ago
who needs more friends on here go to my profile and hit thank you button and friend request and whoever do it first get brianlis
qwelly [4]

Answer:

BET SHORTY

Explanation:

THX

7 0
3 years ago
Read 2 more answers
A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o
Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m

The fundamental frequency of the wire is given by

f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N

The tension in the wire is 67.9064 N

7 0
3 years ago
1. A 455 g mass, hanging at rest on a spring, stretches the spring 22.4 cm beyond its relaxed
pishuonlain [190]

Answer:

19.9 N/m

Explanation:

From the question,

Applying Hook's law

F = Ke.................. Equation 1

Where F = Force on the spring, k = spring constant, e = extension

But the force on the spring is the weight of the mass

Therefore,

mg = ke.................. Equation 2

Where m = mass. g = acceleration due to gravity

make e the subject of the equation

e = mg/e................ Equation 3

Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,

Constant: g = 9.8 m/s²

Substitute these values into equation 3

e = (0.455×9.8)/0.224

e = 19.9 N/m

6 0
3 years ago
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