Answer:
a= 2.667 m/s²
Explanation:
Given that
Initial velocity ,u= 2 m/s
Final velocity ,v= 10 m/s
Time taken ,t= 3 s
As we know that
v = u + at
a=Acceleration ,u=Initial velocity ,v= Final velocity ,t=time
Now by putting the values in the above equation
v = u + at
10 = 2 + a x 3
8 = 3 a
a= 2.667 m/s²
Therefore the acceleration of the biker will be 2.667 m/s²
Force = Mass x Acceleration -> Acceleration = Force/Mass:
36N/3kg = 12 m/s^2
The thickness is 155 nm at t1.
The thickness is 77.3 nm at t2.
The inquiry informs us that the laser light's wavelength is λ=510nm
The plastic rod's refractive index is n=1.30
The transparent coating's refractive index is nr=1.65
Minimum reflection would be required for maximal light transmission into the rod, and it is mathematically described as
2t1=510+10⁻⁹/1.65
t1=510+10⁻⁹/1.65*2
t1=155nm
where m is the interference order, which equals 1.
2t2= {m+1/2} λ/nr
The thickness is t replacing values
t1=155 nm
The highest reflection would occur for minimal light penetration through the rod, and this maximum reflection is mathematically described as
2t2= [m+1/2] λ/nr
t2=77.3 nm
The complete question is- Laser light of wavelength 510 nm is traveling in air and shines at normal incidence onto the flat end of a transparent plastic rod that has n = 1.30. The end of the rod has a thin coating of a transparent material that has refractive index 1.65. What is the minimum (nonzero) thickness of the coating (a) for which there is maximum transmission of the light into the rod; (b) for which transmission into the rod is minimized?
Learn more about reflection here-
brainly.com/question/15487308
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52.1-4.184=47.916 You then either add or subtract this from 68.6 the first temperature of the metal. This will give you your total.
