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Sladkaya [172]
3 years ago
10

What does the subscript tell you?

Chemistry
1 answer:
OverLord2011 [107]3 years ago
8 0
B. The number of atoms of each element in a formula
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AuB4O7 name<br> Element i need help
coldgirl [10]
Can you ask your question more thoroughly?
7 0
3 years ago
Hydrogen is prepared commercially by the reaction of methane and water vapor at elevated temperatures. CH4 (g) + H2 O(g) ⇌ 3H2 (
Damm [24]

Answer:

6.28

Explanation:

Let's consider the following reaction at equilibrium.

CH₄(g) + H₂O(g) ⇌ 3 H₂(g) + CO(g)

The concentration equilibrium constant (Kc) is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

Kc = [H₂]³ × [CO] / [CH₄] × [H₂O]

Kc = 1.15³ × 0.126 / 0.126 × 0.242

Kc = 6.28

8 0
3 years ago
Which statement identifies the element arsenic ?
crimeas [40]

El arsénico puede provocar cáncer en pulmón y piel, e inclusive puede causar otros tipos de cánceres. Se observa una mayor fuerza de asociación entre la exposición crónica al arsénico y los cánceres de piel,El arsénico es un elemento químico de la tabla periódica que pertenece al grupo de los metaloides, también llamados semimetales, se puede encontrar de diversas formas, aunque raramente se encuentra en estado sólido. Se conoce desde la antigüedad y se reconoce como extremadamente tóxi ve

Símbolo: As

Configuración electrónica: [Ar] 3d104s24p3

Masa atómica: 74.9216 u ± 0.00002 u

Número atómico: 33

Electrones por nivel: 2, 8, 18, 5 (imagen)

Grupo, período, bloque: 15, 4, p.

6 0
4 years ago
Ask Your Teacher A 1.04-mole sample of ammonia at 11.0 atm and 25°C in a cylinder fitted with a movable piston expands against a
RUDIKE [14]

Answer:

Explanation:

a) Volume of the gas nRT / P

= 1,04 X 8.3 X 298 / 11 X 10⁵ m³

= 233.85 x 10⁻⁵ m³

= 233 x 10⁻² L

2.33 L

P₁V₁ / T₁ =P₂V₂/T₂

(11 X 2.33) / 298 = (1 X 24.2) / T

T = 281.37 K

= 8.37 degree

b ) w = p x change in volume

= 10⁵ x ( 24.2 - 2.33 ) x 10⁻³ J

= 21.87 X 10² J

2187 J

q  = n x Cp x (25 - 8.37 )

= 1.04 x 35.66x 16.63 J

= 616.65 J

ΔU = Q - W

= 616.65  - 2187 J

= - 1570.35 J

=

=

7 0
3 years ago
A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds
Mariulka [41]

Answer:

\large \boxed{\text{C. 4 m/s}}

Explanation:

At 5 s the body has travelled 10 m.

Between 5 s and 10 s, the body reached 30 m.

Distance travelled = 30 m - 10 m = 20 m

Time = 10 s - 5 s = 5 s

\text{Speed} = \dfrac{\text{ distance}}{\text{time}} = \dfrac{\text{20 m}}{\text{5 s}} = \textbf{4 m/s}\\\\\text{The average speed between 5 s and 10 s is $\large \boxed{\textbf{4 m/s}}$}

4 0
4 years ago
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