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Ket [755]
3 years ago
11

Is milk a solid, liquid or gas at room temperature

Chemistry
2 answers:
astraxan [27]3 years ago
8 0
It is a liquid at room temp.

Olegator [25]3 years ago
6 0
Definitely a liquid
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Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produce
Diano4ka-milaya [45]
To determine the mass of oxygen per gram of sulfur for sulfur dioxide, we simply obtain the ratio of the mass of oxygen and the mass of sulfur produced from the decomposition of sulfur dioxide. All other values given in the problem statement above are just to confuse us that the question is a difficult one. We do as follows:

mass of oxygen per gram sulfur = 3.45 g / 3.46 g
mass of oxygen per gram sulfur = 0.9971 g O2 / g S
4 0
2 years ago
At one time in the Earth’s history, many people thought the world was flat. Which best explains why the model of the Earth is no
GenaCL600 [577]

Answer:

<u>Models are limited by science - the more that was discovered, the better the model could be made.</u>

Explanation:

Models in science are meant to represent things in science. Since science controls the reliability of a model, when science changes, so does the model. Otherwise the model would be pseudoscientific.

5 0
3 years ago
If you change the state of something, say, liquid to solid, is it a physical or chemical change?
Georgia [21]
I believe that it is a chemical change.
4 0
3 years ago
Read 2 more answers
Help please see attached file
OLga [1]

Answer:

balanced equation of glucose

6CO2 + 6H2O----------C6H12O6 + 6O2

in the presence of sun light.

3 0
2 years ago
Write an equilibrium expression for each chemical equation involving one or more solid or liquid reactants or products.
Alex_Xolod [135]

Answer:

a.

Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}

b.

Keq=[O_2]^3

c.

Keq=\frac{[H_3O^+][F^-]}{[HF]}

d.

Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}

Explanation:

Hello there!

In this case, for the attached reactions, it turns out possible for us to write the equilibrium expressions by knowing any liquid or solid would be not-included in the equilibrium expression as shown below, with the general form products/reactants:

a.

Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}

b.

Keq=[O_2]^3

c.

Keq=\frac{[H_3O^+][F^-]}{[HF]}

d.

Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}

Regards!

5 0
2 years ago
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