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konstantin123 [22]
3 years ago
13

một ngẫu lực có momen không đổi M=10KNm tác dugj lên tang của một trục tời xem là đĩa tròn đồng chất có bán kính R =30cm và có t

rọng lượng Q=8KN
Physics
1 answer:
Amanda [17]3 years ago
5 0
Can you speak English pls?
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What is used to measure mass?
defon

Answer:

A balance

Explanation:

Scientists measure mass with a balance, such as a triple beam balance or electronic balance. In science, the volume of a liquid might be measured with a graduated cylinder.

4 0
3 years ago
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Suppose that aliens from a planet orbiting Betelgeuse have eyes similar to human eyes, except that the diameter of their pupils
slega [8]

Answer:

Answered

Explanation:

The data given in the problem

Diameter of a human pupil=0.007 m=7 mm

Diameter of alien pupil=0.5=500 mm

Here we have to calculate the minimum distance at which the alien can see Betelgeuse i.e. the focal length (or the working distance). For this calculation we assume the eye to be a spherical lens.

The focal length and diameter of the lens are related by the formula F=\frac{r}{2} Where r is radius of curvature i.e. d/2

Therefore for the alien, focal length=F=\frac{25}{2}=12.5mm=0.0125F=\frac{25}{2}=12.5mm=0.0125

7 0
3 years ago
Please show work : A particle with mass 2.00 μg and a charge of – 200 nC has a velocity of 3000 m/s in the x-direction. There is
irga5000 [103]

Answer:

 x =4.5 10⁴ m

Explanation:

To find the distance that the particle moves we must use the equations of motion in one dimension and to find the acceleration of the particle we will use Newton's second law

     m = 2.00 mg (1 g / 1000 ug) (1 Kg / 1000g) = 2.00 10-6 Kg

     q = -200 nc (1C / 10 9 nC) = -200 10-9 C

Let's calculate the acceleration

     F = ma

     F = q E

     a = qE / m

     a = -200 10⁻⁹ 1000 / 2.00 10⁻⁶

     a = 1 10² m / s²

Let's use kinematics to find the distance traveled before stopping, where it has zero speed (Vf = 0)

     Vf² = Vo² -2 a x

     0 = Vo² - 2 a x

     x = Vo² / 2a

     x = 3000²/ 2100

     x =4.5 10⁴ m

This is the distance the particule stop, after this distance in the field accelerates in the opposite direction of the initial

Second part

In this case Newton's second law is applied on the y axis

      F -W = 0

      F = w = mg

      E q = mg

      E = mg / q

      E = 2.00 10⁻⁶ 9.8 / 200 10⁻⁹

      E = 9.8 10⁵ C

       

The direction of the field is such that the force on the particle is up, as the particle has a negative charge, the field must be directed downwards F = qE = (-q) E

7 0
4 years ago
A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.69 m above the bottom of the chute with
Veseljchak [2.6K]

Answer:

x = 6.94 m

Explanation:

For this exercise we can find the speed at the bottom of the ramp using energy conservation

Starting point. Higher

            Em₀ = K + U = ½ m v₀² + m g h

Final point. Lower

            Em_{f} = K = ½ m v²

            Em₀ = Em_{f}

            ½ m v₀² + m g h = ½ m v²

            v² = v₀² + 2 g h

             

Let's calculate

             v = √(1.23² + 2 9.8 1.69)

             v = 5.89 m / s

In the horizontal part we can use the relationship between work and the variation of kinetic energy

            W = ΔK

            -fr x = 0- ½ m v²  

               

Newton's second law

              N- W = 0

     

The equation for the friction is

               fr = μ N

               fr = μ m g

We replace

             μ m g x = ½ m v²

             x = v² / 2μ g

Let's calculate

            x = 5.89² / (2 0.255 9.8)

            x = 6.94 m

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4 years ago
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Explanation:

i searched it on gogle

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3 years ago
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