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3 years ago

How and why does air pressure change with altitude in the atmosphere?

1 answer:

5 0

Pressure with Height: pressure decreases with incrementing altitude. The pressure at any caliber in the atmosphere may be interpreted as the total weight of the air above a unit area at any elevation. At higher elevations, there are fewer air molecules above a given surface than a homogeneous surface at lower calibers.

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At one point in the circuit, there is an LED and a resistor in parallel with one another. If you measure the voltage drop across

kifflom [539]

Answer:

C. The voltage drop across the resistor is 2.1V and nothing about the current through the resistor.

Explanation:

When connected in parallel, voltage across the resistances are the same. So if 2.1V was dropped across the LED then 2.1V was also dropped across the resistor. However, this tells us nothing about the current through the resistor. We can find the current across the resistor if we know the resistance of the resistor, but that's about it.

If it were a series connection, then the current would have been the same, but the voltage drop were another story.

7 0

3 years ago

What amount of force is required for a 200 kg grizzly bear to accelerate at 2.5 m/s/<br> s?

Len [333]

Dont mind the top part, hope this helped

5 0

3 years ago

HELP ASAP!! DUE TOMORROW!! FAN & MEDAL!! PLEASE I DON'T UNDERSTAND THIS!! I CAN'T AFFORD TO GET AN F!! ANYTHING WOULD HELP M

USPshnik [31]

If the resulting compound feels hot, then it is exothermic. Otherwise, it is endothermic.

Catalysts and inhibitors both affect the reaction rate of a chemical reaction. A catalyst speeds up the rate of reaction, while an inhibitor does the opposite (slows down the reaction rate).

4 0

3 years ago

Add a vector whose magnitude is 13 with angle 27 degrees to one whose magnitude is 11 with angle 45 degrees? Put the length firs

mafiozo [28]

Answer:

Magnitude of the vector is $23.75\ \text{units}$ and the direction is $35.23^{\circ}$

Explanation:

Magnitude of first vector = $|A| = 13\ \text{units}$

Angle = $\theta_1=27^{\circ}$

Magnitude of second vector = $|B| = 11\ \text{units}$

Angle = $\theta_2=45^{\circ}$

x component of first vector

$A_{x}=|A|\cos\theta_1\\\Rightarrow A_x=13\cos27^{\circ}\\\Rightarrow A_x=11.6\ \text{units}$

y component of first vector

$A_{y}=|A|\sin\theta_1\\\Rightarrow A_y=13\sin27^{\circ}\\\Rightarrow A_y=5.9\ \text{units}$

x component of second vector

$B_{x}=|B|\cos\theta_2\\\Rightarrow B_x=11\cos45^{\circ}\\\Rightarrow B_x=7.8\ \text{units}$

y component of first vector

$B_{y}=|B|\sin\theta_2\\\Rightarrow B_y=11\sin45^{\circ}\\\Rightarrow A_y=7.8\ \text{units}$

Adding the magnitudes

$C_x=A_x+B_x=11.6+7.8\\\Rightarrow C_x=19.4\ \text{units}$

$C_y=A_y+B_y=5.9+7.8\\\Rightarrow C_y=13.7\ \text{units}$

Magnitude of the sum of the vectors would be

$|C|=\sqrt{C_x^2+C_y^2}\\\Rightarrow |C|=\sqrt{19.4^2+13.7^2}=23.75\ \text{units}$

The direction would be

$\theta=\tan^{-1}\dfrac{C_y}{C_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{13.7}{19.4}\\\Rightarrow \theta=35.23^{\circ}$

The magnitude of the vector is $23.75\ \text{units}$ and the direction is $35.23^{\circ}$

4 0

3 years ago

1. The weight of body in air is 20N displaced 5N when emerged into water. The mass of body in water is ??

marishachu [46]

Answer:

5 N

Explanation:

Archimedes' principle indicates that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.

In this case, The weight of an object in air is 20N and it weighs x N when fully immersed in water. So, the weight of the water displaced is given as;

20 − x = 5

Therefore, the weight of the body in water is 5 N.

4 0

1 year ago