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mash [69]
3 years ago
6

During a titration a student found that 20.0cm3 of sodium carbonate solution

Chemistry
1 answer:
vlada-n [284]3 years ago
4 0

Answer: The concentration of Na_2CO_3 required is 0.349mol/dm^3

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of HNO_3 = 1

M_1 = molarity of HNO_3 solution = 0.500 mol/dm^3

V_1 = volume of  HNO_3 solution = 27.9cm^3

n_2 = acidity of Na_2CO_3 = 2

M_1 = molarity of Na_2CO_3 solution =?

V_1 = volume of  Na_2CO_3 solution =  20.0cm^3  

Putting in the values we get:

1\times 0.500\times 27.9=2\times M_2\times 20.0

M_2=0.349mol/dm^3

Therefore, concentration of Na_2CO_3 required is 0.349mol/dm^3

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Explanation :

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\text{Number of electrons} = \frac{1}{2}[V+H-C+A]

where,

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The central atom in this molecule is Carbon, it has 4 electrons in their valence shell.

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V = 4

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By the above hybridization formula, we get

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The number of electrons is 4, this means that the hybridization is sp^{3} and the geometry of the molecule is Tetrahedral.

The geometry of the molecule is shown below.


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Which chemical process generates the atp produced in glycolysis?.
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To solve this kind of  questions, there are many steps:

Know what you are calculating about, it's about the empirical formula, so you need to find out the number of moles of each elements.

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