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3 years ago

If a 15kg object is moving with a velocity of 10m/s, how much kinetic energy does

Physics

1 answer:

vovikov84 [41]3 years ago

5 0

Answer:

Explanation: hii... PFA The image with the steps for the above question. I hope it’s helpful, thanks!

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find the distance traveled in km when the average speed is 60 km per hour and the time taken is 3 and 1/2 hours

Anna35 [415]

Answer:

210 km

Explanation:

60 x 3 1/2 = 210

3 0

3 years ago

7. Why does increasing the mass of an egg increase the chance that it will be damaged in a drop?

12345 [234]

Because if you increase the surface area of such a fragile object there is more space and in turn more of a chance for the object (in this case the egg) to be damaged.

7 0

2 years ago

A small branch is wedged under a 200 kg rock and rests on a smaller object. The smaller object is 2.0 m from the large rock and

Alexxandr [17]

Answer:

$F =326.7 \ N$

$M = 6$

Explanation:

From the question we are told that

The mass of the rock is $m_r = 200 \ kg$

The length of the small object from the rock is $d = 2 \ m$

The length of the small object from the branch $l = 12 \ m$

An image representing this lever set-up is shown on the first uploaded image

Here the small object acts as a fulcrum

The force exerted by the weight of the rock is mathematically evaluated as

$W = m_r * g$

substituting values

$W = 200 * 9.8$

$W = 1960 \ N$

So at equilibrium the sum of the moment about the fulcrum is mathematically represented as

$\sum M_f = F * cos \theta * l - W cos\theta * d = 0$

Here $\theta$ is very small so $cos\theta * l = l$

and $cos\theta * d = d$

Hence

$F * l - W * d = 0$

=> $F = \frac{W * d}{l}$

substituting values

$F = \frac{1960 * 2}{12}$

$F =326.7 \ N$

The mechanical advantage is mathematically evaluated as

$M = \frac{W}{F}$

substituting values

$M = \frac{1960}{326.7}$

$M = 6$

6 0

3 years ago

In which general compass traction is this hurricane moving

Ksenya-84 [330]

Answer:

It looks like its moving north.

Explanation:

3 0

2 years ago

At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coeffi

Flura [38]

The given data is incomplete. The complete question is as follows.

At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coefficient of friction was estimated to be 0.36. Use these data to determine the speed of the car when the driver slammed on (and locked) the brakes. (why does the car's mass not matter?)

Explanation:

Let us assume that v is the final velocity and u is the initial velocity of the car. Let s be the skid marks and $\mu$ be the friction coefficient and m be the mass of car.