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blagie [28]
3 years ago
5

What are motrons in the subject ?

Chemistry
1 answer:
Tems11 [23]3 years ago
5 0

Answer:

Are you talking about this?

A neuroma is growth (benign tumor) that arises in nerve cells. A Morton's neuroma is a swollen, inflamed nerve located between the bones at the ball of the foot...

Explanation:

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dalvyx [7]

Answer:

Explanation:

what subject is this so i can help you

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Which of the followings are true 1,3-BPG? A. It regulates Hb B. It contains a high-energy bond C. It contains two ester bonds D.
weeeeeb [17]

Answer:

D. It contains a phosphate with higher phosphoryl transfer potential than ATP

Explanation:

1,3-Bisphosphoglycerate contains a phosphate group that has high phosphoryl transfer potential than ATP (they can transfer the phosphoryl group to ATP). Other high phosphoryl transfer potential groups include :Creatine kinase and phosphoenolpyruvate.

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How does chlorine react with ethene
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It creates 

<span>THE HALOGENATION OF ALKENES</span>

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3 years ago
Read 2 more answers
What is the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution?
RoseWind [281]

Answer: 0.4M

Explanation:

Given that,

Amount of moles of NaOH (n) = ?

Mass of NaOH in grams = 40.0g

For molar mass of NaOH, use the atomic masses: Na = 23g; O = 16g; H = 1g

NaOH = (23g + 16g + 1g)

= 40g/mol

Since, n = mass in grams / molar mass

n = 40.0g / 40.0g/mol

n = 1 mole

Volume of NaOH solution (v) = 2.5 L

Concentration of NaOH solution (c) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

c = 1 mole / 2.5 L

c = 0.4 mol/L (Concentration in mol/L is the same as Molarity, M)

Thus, the concentration of a solution of a 40.0 g of NaOH in 2.5 L of solution is 0.4 mol/L or 0.4M

7 0
3 years ago
whats the specific heat of an unknown substance if the addition of 800 joules of heat energy caused a 30 gram sample to warm fro
Troyanec [42]

 The specific heat capacity of unknown  substance  is 1.333 g/j/°c


  <u><em> calculation</em></u>

 Specific heat capacity is calculated using  Q= MCΔT  formula

where;

Q(heat)= 800 j

M(mass) = 30 g

C(specific heat  capacity) =?

ΔT( change in temperature)  = 40°c - 20°c = 20°c

make C  the subject of the formula  by diving both side of the formula by MΔT

C  is therefore = Q/MΔT

800j / 30 g x  20°c = 1.333 j/g/°c

7 0
3 years ago
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