Answer: 
= 42.9 atm, 
= 93.4 atm and 
= 7.66 atm
Explanation: The given balanced equation is:
Initial pressure of = 50.560 atm
initial pressure of = 50.500 atm
Let's say the change in pressure is p. Then:
equilibrium partial pressure of = (50.560 - p) atm
equilibrium partial pressure of = (50.500 + p) atm
equilibrium partial pressure of = p atm
Let's plug in the values in it:
on cross multiply:
on rearranging the above equation:
It's a quadratic equation. On solving this equation:
p = 42.9
So, the equalibrium partial pressure of = 42.9 atm
equilibrium partial pressure of = 50.500 + 42.9 = 93.4 atm
equilibrium partial pressure of = 50.560 - 42.9 = 7.66 atm
Answer:
ZnBr2
Explanation:
KNO3 + LiOH -------> no reaction
This is because KNO3 and LiOH completely ionize.in water and form neutral solutions.Since both are neutral no reaction occurs
NH4Cl + LiOH -----> NH3 (aq) + H2O (l) + LiCl(aq)
None of the above products are precipitates
Ca(C2H3O2)2 + 2LiOH -----> Ca(OH)2 (aq) + 2LiC2H3O2 (aq)
ZnBr2 + 2LiOH -----> Zn(OH)2 (s) + LiBr2 ( aq)
Zn(OH)2 thus formed is a white precipitate
However when excess LiOH is added Zn(OH)2 precipitate will dissolve to give a clear solution of Li2ZnO2 .
You can remember this by the fact that Na,K,Rb,Cs,Ca,Sr,Ba hydroxides are soluble in water and all other hydroxide are precipitated in water
Zn(OH)2 (s) + 2 LiOH ------> Li2ZnO2(aq) + 2 H2O ( l)
Answer:
sharing of electron
Explanation:
As seen in carbon. carbon has four electrons in his outermost shell and needs for electron by sharing of electrons it can gain it by another carbon
Answer: (22.98977 g Na/mol) + (1.007947 g H/mol) + (12.01078 g C/mol) + ((15.99943 g O/mol) x 3) = 84.0067 g NaHCO3/mol
9.
(1.20 g NaHCO3) / (84.0067 g NaHCO3/mol) = 0.0143 mol NaHCO3
10.
Supposing the question is asking about "how many moles" of CO2. And supposing the reaction to be something like:
NaHCO3 + H{+} = Na{+} + H2O + CO2
(0.0143 mol NaHCO3) x (1 mol CO2 / 1 mol NaHCO3) = 0.0143 mol CO2 in theory
11.
n = PV / RT = (1 atm) x (0.250 L) / ((0.0821 L atm/K mol) x (298 K)) = 0.0102 mol CO2
12.
(0.0143 mol - 0.0102 mol) / (0.0143 mol) = 0.287 = 28.7%
Explanation:
Decantation<span>Decantation is a process for the separation of mixtures, by removing a layer of liquid, generally one from which a precipitate has settled. The purpose may be either to produce a clean decant, or to remove undesired liquid from the precipitate (or other layers). Separate liquids
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