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hodyreva [135]
4 years ago
10

The accompanying graph represents the theoretical relationship between the volume and the temperature of a gas under constant pr

essure. image According to this graph, the volume of the gas is (5 points) Select one: a. directly proportional to the square of the temperature b. directly proportional to the temperature c. inversely proportional to the temperature d. inversely proportional to the square of the temperature

Physics
2 answers:
nasty-shy [4]4 years ago
6 0

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

Direct relationship is defined as the relationship in which if one variable increases, the other also increases and vice-versa.

x\propto y

where, 'x' and 'y' are two variables.

Indirect relationship is defined as the relationship in which if one variable increases, the other variable decreases and vice-versa.

x\propto \frac{1}{y}

where, 'x' and 'y' are two variables.

In the question, the two variables are Temperature and Volume and to determine the proportionality of the two variables, we will look at the slope of the graph.

If the slope of the graph is positive, then these variables follow direct proportionality and if the slope is negative, then these variables follow inverse proportionality.

Slope of the graph is calculated by using the formula:

\text{Slope}=\frac{y_2-y_1}{x_2-x_1}

\text{Slope}=\frac{800-600}{80-60}=\frac{200}{20}=10

As, the slope is positive, so the volume and temperature follow direct proportionality.

Hence, the correct answer is Option b.

kipiarov [429]4 years ago
4 0

b. directly proportional to the temperature Based on the options given, the most likely answer to this query is volume of the gas is directly proportional to the temperature.Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
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A block, M1=10kg, slides down a smooth, curved incline of height 5m. It collides elastically with another block, M2=5kg, which i
erma4kov [3.2K]

Answer:

2.86 m

Explanation:

Given:

M₁ = 10 kg

M₂ = 5 kg

\mu_k = 0.5

height, h = 5 m

distance traveled, s = 2 m

spring constant, k = 250 N/m

now,

the initial velocity of the first block as it approaches the second block

u₁ = √(2 × g × h)

or

u₁ = √(2 × 9.8 × 5)

or

u₁ = 9.89 m/s

let the velocity of second ball be v₂

now from the conservation of momentum, we have

M₁ × u₁ = M₂ × v₂

on substituting the values, we get

10 × 9.89 = 5 × v₂

or

v₂ = 19.79 m/s

now,

let the velocity of mass 2 when it reaches the spring be v₃

from the work energy theorem,  we have

Work done by the friction force = change in kinetic energy of the mass 2

or

0.5\times5\times9.8\times2 = \frac{1}{2}\times5\times( v_3^2-19.79^2)

or

v₃ = 20.27 m/s

now, let the spring is compressed by the distance 'x'

therefore, from the conservation of energy

we have

Energy of the spring =  Kinetic energy of the mass 2

or

\frac{1}{2}kx^2=\frac{1}{2}mv_3^2

on substituting the values, we get

\frac{1}{2}\times250\times x^2=\frac{1}{2}\times5\times20.27^2

or

x = 2.86 m

8 0
3 years ago
What is the weight of a feather (mass = 0.0001 kg) that floats through earth's and the moon's atmospheres?
olya-2409 [2.1K]

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The feather's weight is . . .

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On the Moon:  (0.0001 kg) x (1.62 m/s²) = <em>0.000162 N</em>

The presence or absence of atmosphere makes no difference.  In fact, the numbers would be the same if the feather were sealed in a jar, or spinning wildly in a tornado, or hanging by a thread, or floating in a bowl of water or chicken soup.  Weight is just the force of gravity between the feather and the Earth.  It's not affected by what's around the feather, or what's happening to it.

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3 years ago
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dalvyx [7]
There are lots of variables that directly and indirectly contribute to the presence of gas on a surface
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Answer:  Point A is the answer for the potential energy. Point D is the answer for the kinetic energy.

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