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nadezda [96]
3 years ago
11

If you stretch back a rubber band and release it, it shoots across the room. What type of energy conversion has occurred?

Chemistry
2 answers:
MAVERICK [17]3 years ago
5 0
<span>Elastic to mechanical is the energy conversion that occurs. Elastic, the pulling back and stretching of the rubber band, mechanical is the release!</span>
Crank3 years ago
4 0

Answer: elastic to mechanical

Explanation: According to the law of conservation of energy, energy can neither be created nor be destroyed. It can only be transformed from one form to another.

Elastic energy is the energy stored as a result of applying a force to deform an elastic object. The energy is stored until the force is removed. When the force is removed,  the object gets back to its original shape.The deformation can involve compressing, stretching or twisting of an object.

Mechanical energy is the energy possessed by a body by virtue of its position and motion.

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207 is the mass number. 82 would be the atomic number
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Explain the significance of this quote, “Heisenberg may have slept here.”
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Umm...Well...

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Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes formula hydroch
matrenka [14]

Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.


Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.

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On adding HCl (strong acid) in water, it will completely dissociates into ions (H^{+} and Cl^{-}) and thus, it is a strong electrolyte.

  • Sodium hydroxide, NaOH

On adding NaOH (strong base) in water, it will completely dissociates into ions (Na^{+} and  OH^{-}) and thus, it is a strong electrolyte.

  • Formic acid, HCOOH

On adding HCOOH (weak acid) in water, it will partially dissociates into ions (H^{+} and  HCOO^{-}) and thus, it is a weak electrolyte.

  • Methyl amine, CH_3NH_2

On adding CH_3NH_2 (weak base) in water, it will partially dissociates into ions (CH_3NH_3^{+} and  OH^{-}) and thus, it is a weak electrolyte.

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On adding KCl in water, it will completely dissociates into ions (K^{+} and  Cl^{-}) and thus, it is a strong electrolyte.

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On adding C_2H_5OH in water, it will not dissociates into ions  and thus, it is a nonelectrolyte.

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On adding C_{12}H_{22}O_{11} in water, it will not dissociates into ions  and thus, it is a nonelectrolyte.

3 0
3 years ago
A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling
aniked [119]

<u>Answer:</u> The mass of glucose in final solution is 0.420 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}        .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated glucose solution

M_2\text{ and }V_2 are the molarity and volume of diluted glucose solution

We are given:

M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL

Putting values in above equation, we get:

0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g

Hence, the mass of glucose in final solution is 0.420 grams

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C. inorganic does not contain carbon
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