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Alina [70]
2 years ago
12

Am I correct or is there more?

Mathematics
1 answer:
inn [45]2 years ago
4 0

20/25 is one I think

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Elaine Mellon earns $17.80 per hour as an electric billing specialist for a legal clinic. How many hours per week must she work
Nuetrik [128]

Answer:

17.80/676.4= $38

Step-by-step explanation:

8 0
3 years ago
What is factored form of the expression 16st+15t<br> ​
svet-max [94.6K]

Answer:

t(16s+15)

Step-by-step explanation:

The highest common factor of 16st+15t is t.

t(16s) + t(15)

Factor.

t(16s+15)

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What is the slope of the line that contains these points?
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(15,-10) (17,2)
(2+10)/(17-15)= 12/2 = 6
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5 0
3 years ago
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Calcula la densidad de una barra metálica cuyas dimensiones son 8.53 cm x 2.4 cm x 1.0 cm. La masa de la barra es de 5289 mg.
musickatia [10]

Answer:

v=a×b×c

v=8.53 cm ×2.4 cm ×1.0 cm

d=m/v

d=52.7064g

20.472 cm3

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5 0
2 years ago
A random sample is drawn from a normally distributed population with mean μ = 31 and standard deviation σ = 1.9. Calculate the p
lesya692 [45]

Answer:

For sample size n = 39 ; P(X < 31.6) = 0.9756

For sample size n = 76 ; P(X < 31.6) = 0.9970

Step-by-step explanation:

Given that:

population mean μ = 31

standard deviation σ = 1.9

sample mean  \overline X = 31.6

Sample size n                 Probability

39

76

The probabilities that the sample mean is less than 31.6 for both sample size can be computed as  follows:

For sample size n = 39

P(X < 31.6) = P(\dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}})

P(X < 31.6) = P(\dfrac{31.6 - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{39}}})

P(X < 31.6) = P(Z< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{39}}})

P(X < 31.6) = P(Z< \dfrac{0.6}{\dfrac{1.9 }{6.245}})

P(X < 31.6) = P(Z< 1.972)

From standard normal  tables

P(X < 31.6) = 0.9756

For sample size n = 76

P(X < 31.6) = P(\dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}})

P(X < 31.6) = P(\dfrac{31.6 - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{76}}})

P(X < 31.6) = P(Z< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{76}}})

P(X < 31.6) = P(Z< \dfrac{0.6}{\dfrac{1.9 }{8.718}})

P(X < 31.6) = P(Z< 2.75)

From standard normal  tables

P(X < 31.6) = 0.9970

6 0
3 years ago
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