Answer:
377 choices
Step-by-step explanation:
From the above question, we are told that
A restaurant offers 6 choices of appetizer, 8 choices of main meal and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses.
Let us represent each choice by :
A = Appetizer = 6
M = Main meal = 8
D = Dessert = 5
a) The combination of the 3 choices together
AMD=6 × 8 × 5=240
b) AM= Appetizer and Main meal
= 6 × 8 = 48
c) AD= Appetizer and Dessert
= 6 × 5 = 30
d) MD = Main meal × Dessert
= 8 × 5 = 40
e) A,M,D (each alone)=
Appetizer + Main meal + Dessert
= 6 + 8 + 5
= 19
Assuming all choices are available, how many different possible meals does the restaurant offer?
This is calculated as:
AMD + AM + AD + MD + A,M,D
240 + 48 + 30 + 40 + 19
= 377 choices
Answer:
A
Step-by-step explanation:
Let us start with B = 90
That would mean that each of the other 2 angles must add to 90 which makes each of them 45.
But the question doesn't allow that. B has to be greater than 90 which means that the other two angles must be less that 45 each.
the only answer that does that is A
Answer:
Not Sure
Step-by-step explanation:
Here's something that might help though:
Do 8% of 20
Then 14% of 20
That's all I got for ya... sorry, I tried my best!
