Question

An aluminum wing on a passenger jet is 35 m long when its temperature is 17°C. At what temperature would the wing be 3 cm (0.03 m) shorter?

Answer 1

Answer:

53.32°C

Explanation:

Length of the aluminium wing = 35 m

Change in length of aluminium wing = 0.03 m

The linear expansion coefficient of aluminium $\alpha =23.6\times 10^{-6}/^{\circ}C$

We know that change in length is given by $\Delta L=L\alpha \Delta T$

So $0.03=35\times 23.6\times 10^{-6}\Delta T$

$\Delta T=36.32^{\circ}C$

So final temperature $=T_I+\Delta T=17+36.32=53.3196^{\circ}C$