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3 years ago

How is momentum conserved in a system in which two satellites connect?

Physics

2 answers:

Zielflug [23.3K]3 years ago

7 0

Answer:

The one satellite has all the momentum before they connect, and then afterwards they share it.

Explanation:

I took the test and I got it correct.

Hope this helps! :)

STALIN [3.7K]3 years ago

4 0

I think the correct answer from the choices listed above is the first option. The one satellite has all the momentum before they connect, and then afterwards they share it. <span>For a collision occurring between object 1 and object 2 in an isolated system, the total </span>momentum<span> of the two objects before the collision is equal to the total </span>momentum<span> of the two objects after the collision.</span>

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A 20000 kg railroad car is rolling at 1.00 m/s when a 1000 kg load of gravel is suddenly dropped in. part a what is the car's sp

Talja [164]

Using conservation of energy and momentum we get m1*v1=(m1+m2)*v2 so rearranging for v2 and plugging the given values in we get:
(200000kg*1.00m/s)/(21000kg)=.952m/s

8 0

3 years ago

Find the current i in:

lawyer [7]

Answer:

I = 24 A

Explanation:

This is Parallel Circuit and it is the first principle of parallel circuit that voltage will be equal in all components in the circuit

It includes 10 resistors Therefore the voltage across,

R1 = R2 = R3 = R4 = R5 = R6 = R7 = R8 = R9 = R10 = voltage in battery

We will apply Ohm's Law to each resistor to find its current because we know the voltage across each resistor is 12 V and the resistance of each resistor is 5Ω

I (R1) = E (R1) / R1

I (R1) = 12v / 5Ω

I (R1) = 2.4 A

The value resistance E of all resistors are same therefore by applying the formula above the value of current in all resistors will be 2.4 A

The Total current in the circuit will be

I (total) = I (1) + I (2) + I (3) + I (4) + I (5) + I (6) + I (7) + I (8) + I (9) + I (10)

I (total) = 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4 + 2.4

I (total) = 24 A

5 0

3 years ago

What can you say about the magnitudes of the forces that the balloons exert on each other?

maxonik [38]

Answer:

$F_G=G. \frac{m_1.m_2}{R^2}$ gravitational force

$F=\frac{1}{4\pi \epsilon_0} \times \frac{q_1.q_2}{R^2}$ electrostatic force

Explanation:

The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.

The Mutual force of gravitational pull that they exert on each other can be given as:

$F_G=G. \frac{m_1.m_2}{R^2}$

where:

$G=$ gravitational constant $=6.67\times 10^{-11} m^3.kg^{-1}.s^{-2}$

$m_1\ \&\ m_2$ are the masses of individual balloons

$R=$ the radial distance between the center of masses of the balloons.

But when there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.

Given as:

$F=\frac{1}{4\pi \epsilon_0} \times \frac{q_1.q_2}{R^2}$

where:

$\rm \epsilon_0= permittivity\ of\ free\ space$

$q_1\ \&\ q_2$ are the charges on the individual balloons

R = radial distance between the charges.

3 0

3 years ago

The Robinson projection map is considered very useful because

Vladimir79 [104]

Hello,
The question states: <span>The Robinson projection map is considered very useful because...
The answer is $\boxed{because \ most \ distances, \ sizes, \ and \ shapes \ are \ accurate.}$

Hope this helped!

~FoodJunky
</span>

7 0

3 years ago

Two balls of equal size are dropped from the same height from the roof of a building. the mass of ball a is twice that of ball b

Sindrei [870]

The mass of ball a is twice the mass of ball b:
$m_a = 2 m_b$
This means that the initial potential energy of ball a ( $U_a = m_a gh=2 m_b gh$ ) is twice the potential energy of ball b ( $U_b = m_b g h$ ):
$U_a = 2 U_b$
When the two balls reach the ground, the potential energy of each ball has converted into kinetic energy (since now their altitude is h=0), because the total mechanical energy of each ball must be conserved. Therefore:
$K_a = U_a$
$K_b = U_b$
and so the kinetic energy of ball a must be twice the kinetic energy of ball b:
$K_a = 2 K_b$

8 0

3 years ago

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