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zheka24 [161]
3 years ago
11

How is momentum conserved in a system in which two satellites connect?

Physics
2 answers:
Zielflug [23.3K]3 years ago
7 0

Answer:

The one satellite has all the momentum before they connect, and then afterwards they share it.

Explanation:

I took the test and I got it correct.

Hope this helps! :)

STALIN [3.7K]3 years ago
4 0
I think the correct answer from the choices listed above is the first option. The one satellite has all the momentum before they connect, and then afterwards they share it. <span>For a collision occurring between object 1 and object 2 in an isolated system, the total </span>momentum<span> of the two objects before the collision is equal to the total </span>momentum<span> of the two objects after the collision.</span>
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A +26.3 uC charge qy is repelled by a force
Musya8 [376]

Answer:

+1.46×10¯⁶ C

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C

Force (F) = 0.615 N

Distance apart (r) = 0.750 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Charge 2 (q₂) =?

The value of the second charge can be obtained as follow:

F = Kq₁q₂ / r²

0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²

0.615 = 236700 × q₂ / 0.5625

Cross multiply

236700 × q₂ = 0.615 × 0.5625

Divide both side by 236700

q₂ = (0.615 × 0.5625) / 236700

q₂ = +1.46×10¯⁶ C

NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C

5 0
3 years ago
Electronic signals are converted into a ____ when transmitted through fiber-optic cables.
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Electronic signals are converted into a 'ray of light' -
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4 years ago
A body of mass 250g is release from the top of a building. if the body hits the ground with a velocity of 4m/s, calculate th hei
Nutka1998 [239]

\purple{\maltese}\large\underline{\underline{\sf\:\: Given :}} \\

» Mass ( m ) of the body = 250 g

» final velocity of the body = 4 m/s

\\\purple{\maltese}\large\underline{\underline{\sf\:\: To \: \: Find :}}  \\

» The height of the Building= ??

\\\purple{\maltese}\large\underline{\underline{\sf\:\: Solution :}} \\ \\

★ <u>Height of the </u><u>building </u><u>by the principal of conservatio</u>n;

\\\\\begin{gathered}\purple{\maltese}\large\underline{\underline{\sf\:\: using \: formula :}} \\ \\\end{gathered}

\bigstar \: \underline{ \boxed{\sf { \pink{ \:  \frac{1}{2}  \: \: mv { }^{2} =  \: mgh \:    }}}}

\\  \: \: \underline{\textsf {Putting values \: in \: the \: \: given \: formula :}} \\

\\  \sf \implies \:  \frac{1}{2}  \: \: mv { }^{2} =  \: mgh \:     \\

\\  \sf \implies \:  \frac{v {}^{2} }{2}  \: \: =  \: gh \:     \\

\\  \sf \implies \:   h \: = \frac{v {}^{2} }{2g}  \: \: \:     \\

\\  \sf \implies \:   h \: = \frac{16 }{20}  \: \: \:     \\

\\  \sf \implies \:   h \: = 0.8  \: \: \:   m  \\

\\  \sf \implies \:   h \: = 80  \: \: \:   cm  \\

henceforth , The height of the Building is <u>0.8 m or 80 cm</u> ..!!!

5 0
2 years ago
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