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Marizza181 [45]
3 years ago
6

John is traveling north at 20 meters/second and his friend Betty is traveling south at 20 meters/second. If north is the positiv

e direction, what are John and Betty's speeds? -20 meters/second, 20 meters/second 20 meters/second, 20 meters/second -20 meters/second, -20 meters/second 0 meters/second, 40 meters/second Done
Physics
2 answers:
Alexxx [7]3 years ago
4 0

Answer:

20 meters/second -20 meters/second

Explanation:

John is travelling north at 20 meters/second. If north is the positive direction, then John is travelling at +20 meters/second, or just 20 m/s.

Betty is travelling south at 20 meters/second, then she is travelling in the negative direction, making her speed -20 meters/second.

Tpy6a [65]3 years ago
3 0
I think it's just 20/20
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PLEASE HELP ASAP
77julia77 [94]

Answer:

<em>The first choice (32m/s) is the closest to the answer</em>

Explanation:

The magnitude of a vector is the distance between the initial and the end point of the vector.

Being Vx and Vy the horizontal and vertical components of the vector V respectively, the magnitude of V is calculated as:

\mid \vec{V} \mid =\sqrt{V_x^2+V_y^2}

The components of the velocity of the physics student's projectile launcher are Vx=28 m/s and Vy=15 m/s.

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\mid \vec{V} \mid =\sqrt{28^2+15^2}

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\mid \vec{V} \mid =31.8 \ m/s

The first choice (32m/s) is the closest to the answer

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3 years ago
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