Answer:
Explanation:
In the diagram there three gears in which gear 1 is input gear ,gear 2 is idle gear and gear 3 is out put gear.
Lets take
All external matting gears will rotates in opposite direction with respect to each other.
So the speed of gear third can be given as follows
Answer :
The number of gold atoms in nanogram is,
The number of gold atoms in picogram is,
Explanation :
As we know that the molar mass of gold is, 196.97 g/mole. That means, 1 mole of gold has 196.97 grams of mass of gold.
As we know that,
1 mole contains number of atoms.
First we have to determine the number of gold atoms in a nanogram.
As, 196.97 grams of gold contains number of gold atoms
And, 1 grams of gold contains number of gold atoms
So, nanograms of gold contains
number of gold atoms
The number of gold atoms in nanogram is,
Now we have to determine the number of gold atoms in a picogram.
As, 196.97 grams of gold contains number of gold atoms
And, 1 grams of gold contains number of gold atoms
So, picograms of gold contains
number of gold atoms
The number of gold atoms in picogram is,
Answer:
diameter of the sprue at the bottom is 1.603 cm
Explanation:
Given data;
Flow rate, Q = 400 cm³/s
cross section of sprue: Round
Diameter of sprue at the top = 3.4 cm
Height of sprue, h = 20 cm = 0.2 m
acceleration due to gravity g = 9.81 m/s²
Calculate the velocity at the sprue base
= √2gh
we substitute
= √(2 × 9.81 m/s² × 0.2 m )
= 1.98091 m/s
= 198.091 cm/s
diameter of the sprue at the bottom will be;
Q = AV = (π/4) ×
= √(4Q/π
)
we substitute our values into the equation;
= √(4(400 cm³/s) / (π×198.091 cm/s))
= 1.603 cm
Therefore, diameter of the sprue at the bottom is 1.603 cm