Answer:
A. 7199.55 volts
B. 120A
Explanation:
In this question we have the
line voltage = VLL = 12470volts
Phase current = Iph = 120 amps
A.)
We are to calculate the line-to-neutral/phase voltage here
VLL = √3VL-N
VL-N = VLL/√3
VL-N = 12470/√3
This gives a line to neutral phase/voltage of 7199.55 volts.
B.
We are to calculate the line current here:
In this connection, the line current and the phase current are equal
ILL = Iph = 120A
Answer:
minimum deceleration = 12.5 ft/s²
Explanation:
Data provided in the question:
Initial speed of the car, u = 50 ft/s
Distance to cover, s = 100 ft
Final speed of the car = 0 ft/s [ ∵ as the car stops ]
Now,
from the Newton's equation of motion
we have
v² - u² = 2as
a is the acceleration
on substituting the respective values, we get
0² - 50² = 2 × a × 100
or
- 2500 = 200a
or
a = - 12.5 ft/s²
Here, the negative sign depicts the deceleration.
Answer:
v₂ = 1.25 m/s
Explanation:
given,
inlet velocity, v₁ = 5 ft/s
inlet Area = A = 10 ft²
outlet velocity, v₂ = ?
outlet Area = 4 A
= 4 x 10 = 40 ft²
Using continuity equation
A₁ v₁ = A₂ v₂
10 v₁ = 40 v₂
v₂ = 1.25 m/s
Hence, the exit velocity of the water through the duct is equal to 1.25 m/s.
