Answer:
Explanation:
In magnetic field , charged particle will have circular path . Let the radius of their circular path be r₁ and r₂ . Let their velocity at the time of entering magnetic field be v₁ and v₂ .
The velocity with which they will come out of electric field can be measured from following equation
Eq = 1/2 m v² , E is electric field , q is charge on the particle , m is mass and v is velocity .
v² = 2Eq / m
radius of circular path can be measured by the following expression
m v² / r = Bqv
2Eq / r = Bqv
r = 2Eq / Bqv
= 2E / Bv
r² = 4E² / B²v²
= 4E²m / B²x 2Eq
since E , B and q are constant
r² = K . m
r₂² / r₁² = m₂ / m₁
1.5²
m₂ / m₁ = 1.5²
= 2.25
Answer:
This is not a question, but a statement. The concept that the work done is equal to the input work on a simple machine is called ideal machine. An ideal machine has 100% efficiency which means that there is no loss. All the amount of input work is equal to the useful output of the machine.
Explanation:
Answer:
Yes, both of them are correct.
Here are some units that can
never represent work:
-- kilogram
-- meter
-- second
-- volt
-- newton
-- light-year
-- mile
-- Pascal
-- lumen
-- Smoot
-- fortnight
-- Hertz
-- inch
-- week
-- ohm
-- quart
-- pound
-- ampere
-- furlong
-- pint
-- dollar
-- acre
-- bushel
-- horsepower
-- gallon
-- liter
-- yard
-- Watt
-- month
-- dram
-- hectare
-- farad
-- Ångstrom
-- shekel
-- decibel
-- radian
-- Scoville
