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sesenic [268]
3 years ago
9

When a board with a box on it is slowly tilted to larger and larger angle, common experience shows that the box will at some poi

nt "break loose" and start to accelerate down the board.The box begins to slide once the component of gravity acting parallel to the boardequals the force of static friction. Which of the following is the most general explanation for why the box accelerates down the board?(A) The force of kinetic friction is smaller than that of static friction, but Fg remains the same.(B) Once the box is moving, Fg is smaller than the force of static friction but larger than the force of kinetic friction.(C) Once the box is moving, Fg is larger than the force of static friction.(D) When the box is stationary, Fg equals the force of static friction, but once the box starts moving, the sliding reduces the normal force, which in turn reduces the friction.
Physics
1 answer:
nydimaria [60]3 years ago
6 0

Answer:

Correct option is A -  The force of kinetic friction is smaller than that of static friction, but Fg remains the same.

Explanation:

(A) The force of kinetic friction is smaller than that of static friction, but Fg remains the same

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The cunninghams are moving across the country. Mr.cunningham leaves 2.5 hours before mrs.cunningham. If he averages 40 mph and s
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When she starts out, he is (40x2.5)= 100 miles ahead of her.

She gains (65-40)= 25 miles on him every hour.

It takes her (100/25)= 4 hours to catch up to him.

5 0
3 years ago
An air conditioner running with R-134a on a cycle executed under the saturationdome between the pressure limits of 0.8 MPa and 0
ohaa [14]

Answer:

The COP of the system is = 4.6

Explanation:

Given data

Higher pressure  = 1.8 M pa

Lower pressure = 0.12 M pa

Now we have to find out high & ow temperatures at these pressure limits.

Higher temperature corresponding to pressure 1.8 M pa

T_{H} = 62.9 °c = 335.9 K

Lower temperature corresponding to pressure 0.2 M pa

T_{L} = - 10.1 °c = 262.9 K

COP of the system is given by

COP = \frac{T_{L} }{T_{H} -T_{L}   }

COP = \frac{335.9}{335.9 -262.9}

COP = 4.6

Therefore the COP of the system is = 4.6

8 0
3 years ago
You can tell from reading this passage that -
Romashka-Z-Leto [24]

Answer: B or "diamonds are rare,valuable gems".

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since the link does not show very much, I don't know if A is correct or not. D is incorrect because that  is an opinion. C is incorrect.

4 0
3 years ago
Which is an example of a vector quantity
swat32

Answer:

The answer to your question is C

Explanation:

acceleration is a vector quantity because it has both magnitude and direction

4 0
3 years ago
Two blocks of masses M 1 and M 2 are connected by a massless string that passes over a massless pulley as shown in the figure. M
stealth61 [152]

The mass M1 is 7.8 kg

Explanation:

Block M1 is hanging on the string while block M2 is on the frictionless ramp.

We have to write the equations of motion for the two blocks.

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M_1 g - T = M_1 a

where

M_1 is the mass of the block

g=9.8 m/s^2 is the acceleration of gravity

a is the acceleration of the system

- For M2, the only two forces acting on it are the tension in the string T (acting up along the ramp) and the component of the gravity acting down along the ramp, M_2 g sin \theta. So the equation of motion is

T-M_2 g sin \theta = M_2 a

where

M_2 = 13.5 kg is the mass of the 2nd block

\theta=35.5^{\circ} is the angle of the ramp

In order for the two blocks to be in equilibrium, the acceleration must be zero:

a=0

So the two equations become:

M_1 g - T=0\\T-M_2 g sin \theta = 0

Isolating T from the 1st equation,

T=M_1 g

And substituting into the 2nd equation, we can find the value of the mass M_1:

M_1 g - M_2 g sin \theta = 0\\M_1 = M_2 sin \theta = (13.5)(sin 35.5^{\circ})=7.8 kg

Learn more about acceleration and forces:

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7 0
3 years ago
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