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Kitty [74]
3 years ago
7

How is a reflection in a mirror like an echo?

Physics
1 answer:
KiRa [710]3 years ago
3 0

Explanation:

an echo mimics exactly what is said, this is like a mirror because when you look in a mirror every action you make is copied by your reflection

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A crane exerts a net force of 900 N upward on a 750-kilogram car as the crane starts to lift the car from the deck of a cargo sh
melisa1 [442]

Answer: 1.2m/s^2

Explanation: the force exerted on the car is 900N upwards

The mass of the car is 750kg

According to Newton's third law acceleration is proportional to force

F = ma

900 = 750a

a = 900/750

a = 1.2m/s^2

5 0
3 years ago
Which two components must a vector quantity
Lemur [1.5K]

Answer:

d. Direction and magnitude

Explanation:

The two components of a vector are its magnitude and direction.

Magnitude is the quantity of the substance

Direction is the path.

  • Other quantities are called scalar quantities.
  • Scalar quantities have only magnitude but no direction.

Examples of vector quantities are velocity, displacement, acceleration.

4 0
3 years ago
0.A 20-g bullet moving at 1 000 m/s is fired through a one-kg block of wood emerging at a speed of 100 m/s. What is the kinetic
Fiesta28 [93]

Answer:

KE = 0.162 KJ

Explanation:

given,

mass of bullet (m)= 20 g = 0.02 Kg

speed of the bullet (u)= 1000 m/s

mass of block(M) = 1 Kg

velocity of bullet after collision (v)= 100 m/s

kinetic energy = ?

using conservation of momentum

m u = m v + M V

0.02 x 1000 = 0.02 x 100 + 1 x V

20 = 2 + V

V = 18 m/s

now,

Kinetic energy of the block

KE = \dfrac{1}{2}mv^2

KE = \dfrac{1}{2}\times 1 \times 18^2

KE = 162 J

KE = 0.162 KJ

4 0
3 years ago
Similarity of gravity and electromagnetic force
Mashutka [201]

Answer:

Gravity is an attractive force as well as electromagnetic, but electromagnetic attracts and repels.

Explanation:

5 0
3 years ago
A 65 N boy sits on a sled weighing 52 N on a horizontal surface. The coefficient of friction between the sled and the snow is 0.
pogonyaev

Answer:

1.40 N

Explanation:

The magnitude of the frictional force is given by:

F=\mu N

where

\mu is the coefficient of friction

N is the magnitude of the normal reaction

The coefficient of friction for this problem is \mu=0.012. The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so

N=65 N+52 N=117 N

Therefore, the frictional force is

F=\mu N=(0.012)(117 N)=1.40 N

3 0
3 years ago
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