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ArbitrLikvidat [17]

3 years ago

9

A body oscillates with simple harmonic motion along the x axis. Its displacement varies with time according to the equation x =

5 sin (πt + π/3). What is the phase of the motion (in rad) at t = 2 s?

1 answer:

frutty [35]3 years ago

7 0

Answer:

θ = (7π / 3) rad

Explanation:

given,

displacement of simple harmonic motion along x-axis

equation is given as

x = 5 sin (π t + π/3 )

general equation of simple harmonic motion

x = A sin θ

θ is the phase angle

θ = π t + π/3

at t = 2 s

$\theta =\pi \times 2 +\dfrac{\pi}{3}$

$\theta =\dfrac{7\pi}{3}\ rad$

Phase of the motion at t =2 s is θ = (7π / 3) rad

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