<u>Answer:</u> The mass of
required is 14.37 g
<u>Explanation:</u>
Molarity is calculated by using the equation:
......(1)
We are given:
Molarity of iron (II) sulfate = 1 M
Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
![\text{Moles of }FeSO_4=(1mol/L\times 0.200L)=0.200mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DFeSO_4%3D%281mol%2FL%5Ctimes%200.200L%29%3D0.200mol)
The chemical equation for the reaction of FeO with sulfuric acid follows:
![FeO+H_2SO_4\rightarrow FeSO_4+H_2O](https://tex.z-dn.net/?f=FeO%2BH_2SO_4%5Crightarrow%20FeSO_4%2BH_2O)
By stoichiometry of the reaction:
If 1 mole of iron (II) sulfate is produced by 1 mole of FeO
So, 0.200 moles of iron (II) sulfate will produce =
of FeO
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
We know, molar mass of
= 71.84 g/mol
Putting values in above equation, we get:
![\text{Mass of }FeO=(0.200mol\times 71.84g/mol)=14.37g](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DFeO%3D%280.200mol%5Ctimes%2071.84g%2Fmol%29%3D14.37g)
Hence, the mass of
required is 14.37 g