The answer for the problem is the option C, which is: <span>C. Angle Bisector Theorem.
The explanation is shown below:
By definition, a bisector of a angle is the line that bisects an angle, or in other words, it is a line that passes through a vertex and cut it into two angles that have the same measure. Keeping this on mind, if a point is located on </span><span>the bisector of an angle, then this point is equidistant from the two sides of the angle, this means that the distance between the point and the two sides are equal.</span>
Do it as simply as possible. 5000 × 2 = 10000. 60 × 10000 = 600000. Because multiplying by a factor of 10 is the easiest possible, always try to get a factor of 10 every time.
For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that 
is such that
Obviously, both limits are 0, so 
is indeed continuous at 
.
Now, for to be differentiable everywhere, its derivative 
must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:
and at this time, we don't know what's going on at , so we omit that case. We want to be continuous, so we require that
from which it follows that 
.
The area of a hexagon with a radius of 5 inches is 86.603.
