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Helen [10]
3 years ago
11

What is a highland? (A) An area of high or hilly land (B) A piece of land surrounded by water on three sides (C) A large area of

land made up of one type of landform (D) A raised, flat-surfaced area bound on one or more sides by cliffs Also, I don't think this is a Physics question, it is just 6th-grade science.
Physics
2 answers:
kozerog [31]3 years ago
8 0

Answer: Option A

Explanation:

A highland, as the name implies, is an extension of mountainous land.

So a highland is any region that is "elevated" compared with the surrounding region.

With this definition, the correct option is A: An area of high or hilly land (obviously, high or hilly compared with the surrounding area)

Karolina [17]3 years ago
3 0

Answer:

A

Explanation:

A Highland is an area of mountains.

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The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate parameter of 1% per day. A s
Bumek [7]

Answer:

2,38kg

Explanation:

Mass in function of time can be found by the formula: m_{(t)} =m_{0} e^{-kt}, where m_{0} is the initial mass, t is the time and k is a constant.

Given that a sample decay 1% per day, that means that after first day you have 99% of mass.

m_{(1)} =m_{0} e^{-k(1)}, but m_{(1)}=\frac{99m_{0} }{100}, so we have \frac{99m_{0} }{100}=m_{0}e^{-k}, then k=-ln(\frac{99}{100})=0.01

Now using k found we must to find m_{(5)}.

m_{(5)}=m_{0}e^{-(0.01)5}=2.5kge^{-0.05} =2.5x0.951=2.38kg

6 0
3 years ago
Velocity must be measured in units of
ohaa [14]
Metres per seconds (m/s)
3 0
3 years ago
Question#7:a) A television uses 1500J of electric energy to produce 1100J 1 point
Vesnalui [34]

Answer:

a.73.3%

b.26.6%

Explanation:

a. The efficiency is the energy output, divided by the energy input, and expressed as a percentage.

#Given the energy input as 1500J and the subsequent output as 1100J, the TV's efficiency is calculated as:

<em />\eta=\frac{E_o}{E_i}\\\\=\frac{1100}{1500}\times 100\%\\\\=73.33\%<em />

Hence, the TV has an efficiency of 33.3%

b. From a above, we know that the TV has an output of 1100J and input of 1500J.

-We therefore calculate it's wastage as the difference between output and input:

<em>Wastage=Energy Input-Energy Output=1500J-1400J=400J</em>

<em />E_w=\frac{E_{wasted}}{E_i}\times 100\%\\\\=(400/1500)\times100\%\\\\=26.67\%<em />

Hence, the TV has wasted of 26.6%

4 0
3 years ago
An ancient club is found that contains 100 g of pure carbon and has an activity of 6.5 decays per second. Determine its age assu
never [62]

Answer:

The age of living tree is 11104 years.

Explanation:

Given that,

Mass of pure carbon = 100 g

Activity of this carbon is = 6.5 decays per second = 6.5 x60 decays/min =390 decays/m

We need to calculate the decay rate

R=\dfrac{-dN}{dt}=\lambda N=\dfrac{0.693}{t_{\frac{1}{2}}}N....(I)

Where, N = number of radio active atoms

t_{\frac{1}{2}}=half life

We need to calculate the number of radio active atoms

For N_{12_{c}}

N_{12_{c}}=\dfrac{N_{A}}{M}

Where, N_{A} =Avogadro number

N_{12_{c}}=\dfrac{6.02\times10^{23}}{12}

N_{12_{c}}=5.02\times10^{22}\ nuclie/g

For N_{c_{14}}

N_{c_{14}}=1.30\times10^{-12}N_{12_{c}}

N_{c_{14}}=1.30\times10^{-12}\times5.02\times10^{22}

N_{c_{14}}=6.526\times10^{10}\ nuclei/g

Put the value in the equation (I)

R=\dfrac{0.693\times6.526\times10^{10}\times60}{5700\times3.16\times10^{7}}

R=15.0650\ decay/min g

100 g carbon will decay with rate

R=100\times15.0650=1507\ decay/min

We need to calculate the total half lives

(\dfrac{1}{2})^{n}=\dfrac{390}{1507}

2^n=\dfrac{1507}{390}

2^n=3.86

n ln 2=ln 3.86

n=\dfrac{ln 3.86}{ln 2}

n =1.948

We need to calculate the age of living tree

Using formula of age

t=n\times t_{\frac{1}{2}}

t=1.948\times5700

t=11103.6 =11104\ years

Hence, The age of living tree is 11104 years.

5 0
3 years ago
Electrons flowing towards south are deflected towards east by a magnetic
Jet001 [13]

Answer:

The magnetic field is upwards.

Explanation:

You have to use "Right-hand rule", but for electrons, the direction of the magnetic force should be reversed.

5 0
3 years ago
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