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Helen [10]
3 years ago
11

What is a highland? (A) An area of high or hilly land (B) A piece of land surrounded by water on three sides (C) A large area of

land made up of one type of landform (D) A raised, flat-surfaced area bound on one or more sides by cliffs Also, I don't think this is a Physics question, it is just 6th-grade science.
Physics
2 answers:
kozerog [31]3 years ago
8 0

Answer: Option A

Explanation:

A highland, as the name implies, is an extension of mountainous land.

So a highland is any region that is "elevated" compared with the surrounding region.

With this definition, the correct option is A: An area of high or hilly land (obviously, high or hilly compared with the surrounding area)

Karolina [17]3 years ago
3 0

Answer:

A

Explanation:

A Highland is an area of mountains.

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Metallic bonds are responsible for many properties of metals, such as conductivity. Why is this possible? (1 point)
qaws [65]

Answer:

The bonds can shift because valence electrons are held loosely and more freely

Explanation:

Please give brainliest if you can,have a good day<3 :)

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2 years ago
Two similar fans are operating in a room. Fan 1 makes a squeaking noise while running. Fan 2 is silent.
REY [17]

Answer:

a

Explanation:

because it has more energy

8 0
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Earth is about 150 million kilometers from the Sun, and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Us
nalin [4]

Answer:

13 W/m^2

Explanation:

The apparent brightness follows an inverse square law, therefore we can write:

I \propto \frac{1}{r^2}

where I is the apparent brightness and r is the distance from the Sun.

We can also rewrite the law as

\frac{I_2}{I_1}=\frac{r_1^2}{r_2^2} (1)

where in this problem, we have:

I_1 = 1300 W/m^2 apparent brightness at a distance r_1, where

r_1 = 150 million km

We want to estimate the apparent brightness at r_2, where r_2 is ten times r_1, so

r_2 = 10 r_1

Re-arranging eq.(1), we find I_2:

I_2 = \frac{r_1^2}{r_2^2}I_1 = \frac{r_1^2}{(10r_1)^2}(1300)=\frac{1}{100}(1300)=13 W/m^2

5 0
3 years ago
In order to place a satellite into orbit, it requires enough fuel to supply the necessary mechanical energy. Into what types of
nexus9112 [7]

When a satellite is revolving into the orbit around a planet then we can say

net centripetal force on the satellite is due to gravitational attraction force of the planet, so we will have

F_g = F_c

\frac{GM_pM_s}{r^2} = \frac{M_s v^2}{r}

now we can say that kinetic energy of satellite is  given as

KE = \frac{1}{2}M_s v^2

KE = \frac{GM_sM_p}{2r}

also we know that since satellite is in gravitational field of the planet so here it must have some gravitational potential energy in it

so we will have

U = -\frac{GM_sM_p}{r}

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Which of the following is true about wedges?
timofeeve [1]

Answer:

wedges are a type of inclined plane.

Explanation:

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