Answer:
Power P=246.78 KW
Explanation:
Mass of Elevator=4710 Kg
Can carry load =1910 Kg
Total Mass m to be lifted =4710 kg + 1910 Kg =6620 kg
speed = 3.80 m/s ⇒ per second distance traveled (height h) = 3.80 m and time t = 1 s
Using formula of Power P =
P =
P= 6620kg × 9.81 m/s² × 3.80 m / 1s
P= 246780.36 W
P=246.78 KW
Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :
F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
Explanation:
As the given spheres are connected by a thin wire so, the potential on the spheres are the same.
......... (1)
Hence, total charge will be as follows.
= Q = -95.5 nC .......... (2)
Using the above two equations, the final equation will be as follows.
and,
Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.
=
= 82.714 nC
Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.