It depends on how much force there both putting on the box but because it does say the correct answer is C.
Answer:
The answer to your question is below
Explanation:
Data 1
mass 1 = 250
mass 2 = 250 kg
gravity constant = 6.67 x 10⁻¹¹ Nm²/kg²
distance = 8 m
Formula
Substitution
Result
F = 0.000000065 N
Data 2
mass 1 = 1000 kg
mass 2 = 1000 kg
distance = 5 m
Substitution
Result
F = 0.000002667 N
Answer:
The correct option is C
Explanation:
According to third equation of motion, v
2
=u
2
+2ax
Here, u=0 m/s
a=−g and x=−h
Negative sign indicates downward direction. Displacement and acceleration both are downwards.
So,v=±
2(−g)(−h)
We take minus sign because it is downwards.
v=−
2gh
After bouncing. velocity becomes 80% of v, i.e.,
v
′
=+0.8
2gh
(positive sign because the direction of ball has reversed after bouncing and is upwards.
Applying third equation of motion again, for u=v
′
, v=0 and a=−g
v
2
=u
2
+2×a×x
Thus,
0=0.64(2gh)+2(−g)x
or
x=0.64h
power = force x velocity ==> work done/time = force x velocity ==> 33750/t = force x 30 ==> force x time = 33750/30 ==> momentum(P) = 1125 kg-m/s ( since force = momentum/time). P = m x v ==> m= P/v = 1125/30 =37.5 kg.
Density=mass÷volume
density=40.5÷15=2.7